The distance of dodo is 150 cm.
<h3>What is focal length of lens?</h3>
The distance between a lens's center and its focal point is its focal length. A focal point is a location on the principal axis where, following refraction via the lens, light rays parallel to the principal axis either actually meet or appear to meet.
Given parameters:
the focal length of David's lens is: f = 50 cm.
magnification is: m = -0.50
We have to find: distance of dodo, that is, object's distance : u = ?
We know that:
u =f( 1/m -1)
⇒ u = 50(-1/0.50-1) = - 150 cm.
Hence, distance is 150 cm.
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Answer:
the answer is at least 3 feet
Explanation:
In order to ensure that a cable is not affected by electromagnetic interference, it should be at least 3 feet away from fluorescent lighting.
This is because, cables can be adversely affected by electromagnetic interference - which is a disturbance that affects an electrical circuit due to either electromagnetic induction or radiation emitted from an external source - and insulation alone cannot provide adequate protection for these cables.
Therefore, the cables should be kept a few feet away from flourescent lighting in order to prevent this interference.
When you look at an arbitrary point of the sky, but in an other direction away from the sun, you will only see the light that has been redirected because of the atmosphere into our sight. This happens much more often for a blue light rather than red, therefore the sky becomes blue in our view. However, there is also a violet light that is scattered even a little bit more strongly as opposed to blue.
if you want to see a picture that may help you answer your question, google on google images ''prism.''
Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .
Given Information:
Mass = m = 500 kg
Acceleration = a = 10 cm/s²
Required Information:
Magnitude of rightward net force = F = ?
Answer:
Magnitude of rightward net force = 50 N
Explanation:
From the Newton's second law of motion
F = ma
Where m is the mass and a is the acceleration
To get force in Newtons first convert 10 cm/s² into m/s²
10/100 = 0.1 m/s²
F = 500*0.1
F = 50 N
Therefore, the magnitude of rightward net force acting on it is 50 Newtons.
