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joja [24]
3 years ago
10

Which of the following can reduce biodiversity within a natural environment? A. Yucca moths pollinate and feed on yucca plants i

n the Mojave Desert. B. Red-billed oxpeckers eat ticks off of impalas' coats in the grasslands of East Africa. C. Non-native American bullfrogs out-compete native amphibians in the Tropical Andes. D. Giant kangaroo rats enrich the soil for plants with their piles of grass clippings in the California grasslands.
Physics
1 answer:
DaniilM [7]3 years ago
8 0
I wanna say B Red-billed oxpeckers eat ticks off of impalas
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How much work will it take to lift a 2-kg pair of hiking boots 2 meters off the
AnnyKZ [126]

Answer:

Option C - 39.2 J

Explanation:

We are given that;

Mass; m = 2 kg.

Distance moved off the floor;d = 10 m.

Acceleration due to gravity;g = 9.8 m/s².

We want to find the work done.

Now, the Formula for work done is given by;

Work = Force × displacement.

In this case, it's force of gravity to lift up the boots, thus;

Formula for this force is;

Force = mass x acceleration due to gravity

Force = 2 × 9.8 = 19.2 N

∴ Work done = 19.6 × 2

Work done = 39.2 J.

Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.

7 0
3 years ago
Read 2 more answers
What changes would result in a decrease in the gravitational force between two objects? Check all that apply.
REY [17]

<em>I'm sorry, it says check all that apply, however there are no choices given. You should edit, and add the multiple choice answers.</em>

My Answer:

Well if the masses of two objects were both decreased, it would result in a decrease in the gravitational force. So I guess the two objects masses would need to be decreased.

4 0
3 years ago
Choose all the answers that apply.
Serhud [2]
<span>According to Newton's first law of motion:

-- objects at rest will remain at rest unless acted upon by an outside force

-- objects in motion will remain in motion unless acted upon by an outside force


</span>
8 0
3 years ago
What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
2 years ago
A car moving with a speed of 35 m/s sees a child standing in the
zlopas [31]

Answer:

2100 N

Explanation:

v = u + at \\ 0 = 35 + a(5) \\ a =  - 7m {s}^{ - 2}  \\ \\ net \: force \:  = ma \\  = (300)(7) \\  = 2100 \: newtons

6 0
2 years ago
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