(a) g = Gm/r^2
where G=6.67 * 10^-11 Nm^2/kg^2,
m is the mass of the planet,
r is the radius of the planet.
7.0 = (6.67 * 10^-11)/(2500^2) * m
m= (25000000^2 * 9.0)/(6.67 * 10^-11)
m = 8.4333 x 10^24 kg
(b) g=Gm/r^2. This time, the radius is 2500+10000 = 12500km g = (6.67 * 10^-11 * 8.43333*10^18)/(12500^2)
g = 3.6 m/s^2
Answer:
1st, 3rd, and maybe 2nd and 5th it depends
Hey there!
<span>The process by which hot and cold air are transferred in the atmosphere is convection.</span>
Answer:
-63.6m/s
Explanation:
Given parameters:
Initial velocity = 5m/s
Time of flight = 7s
Unknown:
Velocity of the eraser after 7s = ?
Solution:
To solve this problem, we have to use the right motion equation which is given below;
v = u - gt
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity = 9.8m/s²
t is the time taken;
Now insert the parameters and solve for v;
v = 5 - (9.8 x 7)
v = -63.6m/s
(1.6 x 10⁻¹⁹ C) x (300 N/C) = <em>4.8 x 10⁻¹⁷ Newton</em>
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