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Dmitry_Shevchenko [17]
4 years ago
9

The speed of a light wave in a certain transparent material is 0.589 times its speed in vacuum, which is 3.00 x108 m/s. When yel

low light with a frequency of 5.25 x104 Hz passes through this material, what is its wavelength in nanometers? Number 囗 n m
Physics
1 answer:
irakobra [83]4 years ago
8 0

Answer:

The wavelength of the yellow light in given transparent material is <em><u>337 nm</u></em>

Explanation:

Speed of the light in vacuum , c=3.00\times 10^{8}\frac{m}{s}

Therefore speed of light in the given material is v=0.589\times c

=>v=0.589\times 3.00\times 10^{8}\frac{m}{s}=1.767\times 10^{8}\frac{m}{s}

frequency of yellow light , f=5.25\times 10^{14}Hz

Wavelength in the given transparent material , \lambda =\frac{v}{f}=\frac{1.767\times 10^{8}}{5.25\times 10^{14}}m

=> \lambda =3.366\times 10^{-7}m=336.6nm

=>\lambda \simeq 337nm

Thus the wavelength of the yellow light in given transparent material is <em><u>337 nm</u></em>

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move at constant velocity.

Explanation:

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Sunitha can type 1800 words in half an hour. What is her typing speed in words per minute?
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Answer:

60words/minute

Explanation:

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Hence her typing speed in words per minute is 60words/minute

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Consider a double Atwood machine constructed as follows: A mass 4m is suspended from a string that passes over a massless pulley
kenny6666 [7]

Answer:

Hello your question is incomplete attached below is the complete question

Answer : x ( acceleration of mass 4m ) = \frac{g}{7}

The top pulley rotates because it has to keep the center of mass of the system at equilibrium

Explanation:

Given data:

mass suspended = 4 meters

mass suspended at other end = 3 meters

first we have to express the kinetic and potential energy equations

The general kinetic energy of the system can be written as

T = \frac{4m}{2} x^2  + \frac{3m}{2} (-x+y)^2 + \frac{m}{2} (-x-y)^2

T = 4mx^2 + 2my^2 -2mxy  

also the general potential energy can be expressed as

U = -4mgx-3mg(-x+y)-mg(-x-y)+constant=-2mgy +constant

The Lagrangian of the problem can now be setup as

L =4mx^2 +2my^2 -2mxy +2mgy + constant

next we will take the Euler-Lagrange equation for the generalized equations :

Euler-Lagrange  equation = 4x-y =0\\-2y+x +g = 0

solving the equations simultaneously

x ( acceleration of mass 4m ) = \frac{g}{7}

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3 years ago
Which statement best describes a characteristic of gases?
salantis [7]
Assumes the shape and volume of its container 
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3 years ago
Suppose you have two solid bars, both with square cross-sections of 1 cm2. They are both 24.6 cm long, but one is made of copper
vodka [1.7K]

Explanation:

Expression to calculate thermal resistance for iron (R_{I}) is as follows.

             R_{I} = \frac{L_{I}}{k_{I} \times A_{I}}  

where,   L_{I} = length of the iron bar

             k_{I} = thermal conductivity of iron

             A_{I} = Area of cross-section for the iron bar

Thermal resistance for copper (R_{c}) = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]

where,  L_{c} = length of copper bar

             k_{c} = thermal conductivity of copper

            A_{c} = Area of cross-section for the copper bar

Now, expression for the transfer of heat per unit cell is as follows.

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       Q = \frac{(100^{o} - 0^{o})}{\frac{L_{I}}{k_{I}.A_{I}} + \frac{L_{c}}{k_{c}.A_{c}}}

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It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,

                 P = \frac{Q}{T}

Here, T is 1 second so, power conducted is equal to heat transferred.

So,           P = 2.92 watt

Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.

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