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Dmitry_Shevchenko [17]
3 years ago
9

The speed of a light wave in a certain transparent material is 0.589 times its speed in vacuum, which is 3.00 x108 m/s. When yel

low light with a frequency of 5.25 x104 Hz passes through this material, what is its wavelength in nanometers? Number 囗 n m
Physics
1 answer:
irakobra [83]3 years ago
8 0

Answer:

The wavelength of the yellow light in given transparent material is <em><u>337 nm</u></em>

Explanation:

Speed of the light in vacuum , c=3.00\times 10^{8}\frac{m}{s}

Therefore speed of light in the given material is v=0.589\times c

=>v=0.589\times 3.00\times 10^{8}\frac{m}{s}=1.767\times 10^{8}\frac{m}{s}

frequency of yellow light , f=5.25\times 10^{14}Hz

Wavelength in the given transparent material , \lambda =\frac{v}{f}=\frac{1.767\times 10^{8}}{5.25\times 10^{14}}m

=> \lambda =3.366\times 10^{-7}m=336.6nm

=>\lambda \simeq 337nm

Thus the wavelength of the yellow light in given transparent material is <em><u>337 nm</u></em>

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Answer:

Explanation:

Given that,

We have five children.

Each of mass m =30kg

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The four child that sit at the edge are 2m from the centre of the merry go round but the one at the centre is 0m from the centre

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I=Σmi•ri²

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I= I(merry go round) + I(four child)+ I(last child)

The merry go round is assumed to be a solid cylinder, so it is going to have the moment of inertia of solid cylinder

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I(merry go round ) =½ Mr²

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I= I(merry go round) + I(four child) +I(last child )

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while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity o
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Complete question:

while hunting in a cave a bat emits sounds wave of frequency 39 kilo hartz were moving towards a wall with a constant velocity of 8.32 meters per second take the speed of sound as 340 meters per second. calculate the frequency​ reflected off the wall to the bat?

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frequency emitted by the bat, = 39 kHz

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The frequency reflected by the stationary wall to the bat is calculated as;

f_s = f'(\frac{v + v_b}{v} )\\\\f_s = 39978.29(\frac{340 + 8.32}{340} )\\\\f_s = 40,956.56 \ Hz

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