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lina2011 [118]
3 years ago
13

PLSSSSSS HELP ME ASAP

Mathematics
2 answers:
gogolik [260]3 years ago
7 0
A = 2 (w l + h l + h w)

5m = Width
12 = Length
9m = Height

Surface Area = 426
kolezko [41]3 years ago
3 0
Formula
l×w×h=volume
12×5×9=v
540=v
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State the common factor of the terms in the polynomial 5x^2 + 30x^2 - 10x. Then factor the polynomial
tatuchka [14]

Answer:

The common factor is 5x.

The factored polynomial is: 5x(7x - 2)

Step-by-step explanation:

Factor of the numbers:

The common factor of the numbers 5, 30 and 10 is 5, as it is the greater common divisor of them, as found below:

5 - 30 - 10|5

1 - 6 - 2

Factor of the exponents:

Between x^2, x^2 and x, the common factor is the x with the lowest exponent. So x

Common factor

Number multiplied by exponents, so 5x.

Factoring the polynomial:

5x^2 + 30x^2 - 10x = 5x(\frac{5x^2}{5x} + \frac{30x^2}{5x} - \frac{10x}{5x}) = 5x(x + 6x - 2) = 5x(7x - 2)

The factored polynomial is: 5x(7x - 2)

6 0
3 years ago
How do you know if the factors will have negatives or positives in them?
harina [27]

When using factoring by grouping, the replacement terms will both have the same sign of the original middle term. If the last term is negative, then the signs of the factors will have one of each sign with the “stronger” number (the larger absolute value) matching the middle term. hope this helps
8 0
3 years ago
Sadie is saving her money to buy a new pony, which costs $600. She has already saved $75. She earns $50 per week working at the
rodikova [14]

Answer:

A

Step-by-step explanation:

5 0
3 years ago
In a string of 12 Christmas tree light bulbs, 3 are defective. The bulbs are selected at random and tested, one at a time, until
Juliette [100K]

Using the hypergeometric distribution, it is found that there is a 0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

In this problem, the bulbs are chosen without replacement, hence the <em>hypergeometric distribution</em> is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • N is the size of the population.
  • n is the size of the sample.
  • k is the total number of desired outcomes.

In this problem:

  • There are 12 bulbs, hence N = 12.
  • 3 are defective, hence k = 3.

The third defective bulb is the fifth bulb if:

  • Two of the first 4 bulbs are defective, which is P(X = 2) when n = 4.
  • The fifth is defective, with probability of 1/8, as of the eight remaining bulbs, one will be defective.

Hence:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,12,4,3) = \frac{C_{3,2}C_{9,1}}{C_{12,4}} = 0.2182

0.2182 x 1/8 = 0.0273.

0.0273 = 2.73% probability that the third defective bulb is the fifth bulb tested.

More can be learned about the hypergeometric distribution at brainly.com/question/24826394

8 0
2 years ago
Consider the expression √(√625).
const2013 [10]

Answer:

5

Step-by-step explanation:

Square Root - Finding a number that multiplies itself twice into the number within the square root

With this meaning, we need to find a number that multiplies itself into 625.

Finding calculations using exponents will help,

25^2 is equal to 625. Therefore \sqrt{25}

We are not finished, as there is another square root right after, empowering the parenthesis, so what number multiplies itself equals 25?

This would be 5, therefore \sqrt{(\sqrt{625}) } is equal to 5.

6 0
3 years ago
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