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Scrat [10]
3 years ago
7

Jeffrey is making a model of tungsten for his chemistry class. He has foam balls for the protons, neutrons, and electrons. He ha

s added 21 electrons to his model so far. How many more electrons does he need to add to complete his neutral atom of tungsten?
A. 1
B. 22
C. 31
D. 53
Chemistry
1 answer:
mrs_skeptik [129]3 years ago
8 0

Atomic number (Z) of tungsten is 74

Mass number (A) of tungsten is 184

Now:

Atomic number of an element = Number of protons = Number of electrons

Mass number = Number of Protons + Number of neutrons

In the case of tungsten

Total Number of electrons = 74

Jeffrey has already added 21 electrons

Number of electrons needed = 74 - 21 = 53

Ans (D) 53 more electrons are needed to complete the neutral atom of tungsten.

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PLEASE HELP FAST!! How much energy (in calories) is need to melt 3.0 moles of ice?
Viktor [21]

Answer:

Energy

Explanation:

The heat required to change the phase of a substance is given by the equation:

Q= mL (Q= Heat required, m= mass, L= Latent Heat of Fusion/Evaporation/Anything else).

So, according to your values:

Q= 3.0 kg x 333 kJ/Kg

So, Q= 999 kJ

4 0
3 years ago
Consider the reaction between NaCl and AgNO3 to form silver chloride. How much of the insoluble precipitate will be recovered if
yulyashka [42]

Answer:

The correct answer is: 491.2 g AgCl

Explanation:

The balanced chemical equation for the reaction between AgNO₃ and NaCl is the following:

AgNO₃(aq) + NaCl(aq) ⇒ AgCl(s) + NaNO₃(aq)

From the products, <em>silver chloride (AgCl) is an insoluble salt</em>, so it will precipitate as is formed. Moreover, from the balanced equation we can see that 1 mol AgCl is obtained from 1 mol AgNO₃:

1 mol AgCl = 107.8 g + 35.4 g = 143.2 g

1 mol AgNO₃= 107.8 g + 14 g + (3 x 16 g) = 169.8 g

Thus, we have a stoichiometric ratio of 143.2 g AgCl/169.8 g AgNO₃. From the reaction of 582.4 g AgNO₃, the following mass of AgCl will be formed:

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7 0
4 years ago
H
sergiy2304 [10]

Answer:

302.8K

Explanation:

Using Charles law equation;

V1/T1 = V2/T2

Where;

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

V1 = 545L

V2 = 550L

T1 = 27°C = 27 + 273 = 300K

T2 = ?

Using V1/T1 = V2/T2

545/300 = 550/T2

1.82 = 550/T2

Cross multiply

1.82 T2 = 550

T2 = 550/1.82

T2 = 302.8K

3 0
3 years ago
Determine the concentration of an aqueous solution that has an osmotic pressure of 3.9 atm at 37°C if the solute is sodium chlor
Snowcat [4.5K]

Answer:

Concentration for the solution is 0.153 mol/L

Explanation:

Formula for the osmotic pressure is  π = M . R . T . i

where M is molarity (concentration), R the universal constant for gases and T is Absolute T° (T°C + 273)

π = Osmotic pressure.

Let's replace the data given:

3.9 atm =  M . 0.082L.atm/mol.K . 310K

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In this case, we assumed no ion pairing, so i = 1

8 0
3 years ago
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Gnom [1K]

Answer:

5 would be the large intestine

Explanation:

4 0
3 years ago
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