Let the mass of 2500 kg car be and it's velocity be
and the mass of 1500 kg car be
and it's velocity be
.
After the bumping the mass be M and it's velocity be V.
By law of conservation of momentum we have
2500 * 5 + 1500 * 1=4000 * V
V = 14000/4000 = 7/2 = 3.5 m/s
So the velocity of the two-car train = 3.5 m/s
The mass m of the object = 5.25 kg
<h3>Further explanation</h3>Given
k = spring constant = 3.5 N/cm
Δx= 30 cm - 15 cm = 15 cm
Required
the mass m
Solution
F=m.g
Hooke's Law
F = k.Δx
a) Density of the liquid:
b) Weight of the liquid: 1372 N
Explanation:
Translation of the text:
<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>
<em>a) the density of the liquid; </em>
<em>b) the weight of the liquid."</em>
a)
We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as
(1)
where
is the mass of the liquid
is the mass of the vessel
We also know that the total mass M is 5 times the mass of the empty vessel, so we have:
which is the mass of the empty vessel.
Therefore, we can find the mass of the liquid only using (1):
The density of the liquid is given by
where
m = 140 kg (mass of the liquid)
V = 0.170 kL = 170 L = (volume of the liquid, which is equal to the volume of the vessel)
So we get
b)
The weight of a body is given by
where
m is its mass
g is the acceleration due to gravity
For the liquid in this problem, we have
m = 140 kg (mass)
(acceleration due to gravity)
Therefore, its weight is
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