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mart [117]
4 years ago
8

Marcus drove his Honda Prelude for 4 hours at a rate of 55 miles per hour. How far did he travel?

Physics
2 answers:
galben [10]4 years ago
7 0
To solve this, you’d multiply 55 by 4, because he is travelling 55 miles every hour, for four hours, which means 55 miles every hour. The answer would be 220.
lilavasa [31]4 years ago
5 0

Answer : Distance covered is 220 miles.

Explanation :

It is given that,

Speed of Marcus's Honda Prelude, v=55\ miles/hour

Time duration, t=4\ hours

We know that the speed of an object is defined as the distance travelled per unit time.

v=\dfrac{d}{t}

or

d=v\times t

d=55\ miles/hour\times 4\ hours

d=220\ miles

Hence, this is the required solution.      

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Convert 318 meters per second to kilometers per hour
alexgriva [62]

Answer:

1144.8

Explanation:

1 meter per second is equal to 3.6 kilometers per hour

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3 years ago
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A horizontal insulating rod of length 11.8-cm and charge 19 nC is in a plane with a long straight vertical uniform line charge.
SCORPION-xisa [38]

Answer:

11.962337 × 10^-4 N

Explanation:

Given the following :

Length L = 11.8

Charge = 29nC = 29 × 10^-9 C

Linear charge density λ = 1.4 × 10^-7 C/m

Radius (r) = 2cm = 2/100 = 0.02 m

Using the relation:

E = 2kλ/r ; F =qE

F = 2kλq/L × ∫dr/r

F = 2*k*q*λ/L × (In(0.02 + L) - In(0.02))

2*k*q*λ/L = [2 × (9 * 10^9) * (29 * 10^9) * (1.4 * 10^-7)]/ 0.118] = 6193.2203 × 10^(9 - 9 - 7) = 6193.2203 × 10^-7 = 6.1932203 × 10^-4

In(0.02 + 0.118) - In(0.02) = In(0.138) - In(0.02) = 1.9315214

Hence,

(6.1932203 × 10^-4) × 1.9315214 = 11.962337 × 10^-4 N

3 0
4 years ago
If the angle of incidence of a light source to a shiny surface is 30 degrees, what will the angle
Virty [35]
<h3>Answer: D) 30</h3>

Angle of incidence always equals angle of reflection. Think of a tennis ball being hit into a wall. The ball will bounce off at the same angle that it approached with. The angles mentioned are formed through the line called the "normal", which is the line perpendicular to the surface.

5 0
3 years ago
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When you blink your eye, the upper lid goes from rest with your eye open to completely covering your eye in a time of 0.024 s.
dusya [7]

a) Distance moved by the top lid during a blink: 1 cm (estimate)

b) The acceleration is 34.7 m/s^2

c) The final speed is 0.83 m/s

Explanation:

a)

For the purpose of this problem, we can estimate the size of the eye from the top lid to the bottom lid to be 1 cm, so this is the distance moved by the top lid during a blink.

b)

Assuming the motion of the eyelid to be at constant acceleration, we can find the acceleration by using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance covered

u is the initial velocity

t is the time

a is the acceleration

For the eyelid, we have:

u = 0 (it starts from rest)

s = 1 cm = 0.01 m is the distance covered

t = 0.024 s is the time taken

Solving for a, we find the acceleration:

a=\frac{2s}{t^2}=\frac{2(0.01)}{0.024^2}=34.7 m/s^2

c)

The final speed of the upper eyelid can be found by using another suvat equation:

v=u+at

where

v is the final speed

u is the initial speed

a is the acceleration

t is the time

For the eyelid in this problem, we have

u = 0

a=34.7 m/s^2

t = 0.024 s

Substituting, we find the final speed:

v=0+(34.7)(0.024)=0.83 m/s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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Which single force acts on an object in free fall
ICE Princess25 [194]

Answer:

gravity

Explanation:

4 0
3 years ago
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