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3 years ago

4) Kinetic energy is directly related to _______

Physics

1 answer:

TEA [102]3 years ago

6 0

Answer:

4) C.mass

5) C. Potential Energy

Explanation:

4) Kinetic energy (KE) of an object is the energy that it possesses due to its motion. If a mass is in motion ,it has a kinetic energy .

By definition

$Kinetic.Energy=\frac{1}{2}*mass*velocity^{2}$

what matters in Kinetic energy is the mass and the velocity only .

there fore the answer is

C.mass

5) Potential energy is the energy stored in an object, due to the object's position or arrangement.

By definition

$Potential.Energy=mass*gravitaional.Acceleration*height$

in potential energy the height matters.higher the height , higher the energy

therefore the answer is

C.Potential Energy

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Answer:

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3 years ago

Read 2 more answers

A school bus has a mass (including the driver and passengers) of 1.64 times 10^4 kg and is driving north at a speed of 15.2 km/h

Butoxors [25]

Answer:

Explanation:

Given

mass of bus along with travelers travelling in North direction is $m_1=1.6\times 10^4 kg$

speed of bus towards North $v_1=15.2 km/h\approx 4.22\ m/s$

mass of bus travelling in South direction is $m_2=1.578\times 10^4 kg$

speed of bus $v_2=12.2 km/h\approx 3.38\ m/s$

mass of each Passenger in south moving bus $m_0=64.8 kg$

Momentum of North moving bus

$P_1=m_1\times v_1$

$P_1=1.6\times 10^4\times 4.22$

$P_1=6.768\times 10^4 kg-m/s$

Momentum with south moving bus

$P_2=m_2\times v_2+n\cdot m_0\times v_2$

$P_2=(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38$

For total momentum to be towards south

$P_2-P_1$ should be greater than 0

thus for least value of n

$P_2=P_1$

$(1.578\times 10^4+n\cdot 64.8 )\cdot 3.38=6.768\times 10^4$

$1.578\times 10^4+n\cdot 64.8=2.0023\times 10^4$

$n=\frac{4243.6686}{64.8}=65.48\approx 66$

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3 years ago

A 270,000 kg rocket in gravity -free space expels 270 kg of fuel by exerting a force of 360 N on it. Find the magnitude of the a

Brut [27]

F = m a
360 = 270 x a
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3 years ago

The frequency of a certain sound is 440 Mz. What is the wavelength of this sound when the temperature of the air is (a) 20°C; (b

Serggg [28]

Answer:

Explanation:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

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340

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2 years ago