1000 liters = 1 m^3
and
1.3um^3 = 1.3x10^(-6)m^3
multiply both sides of the first equation by 1.3x10^(-6)
1.3x10^(-6) * 1000 liters = 1.3x10^(-6) * 1m^3
1.3x10^(-3) liters = 1.3x10^(-6) m^3
Answer:
3S₈ + 28Br₂ => 8S₃Br₇
Explanation:
Start with either sulfur (S) or bromine (Br) and balance ...
3S₈ + Br₂ => 8S₃Br₇ or S₈ + 7/2Br₂ => S₃Br₇
Balance the remaining reactant ...
3S₈ + 56/2Br₂ => 8S₃Br₇
Remove fractions by multiplying by the fraction's denominator
2(3S₈ + 56/2Br₂ => 8S₃Br₇) => 6S₈ + 56Br₂ => 16S₃Br₇
Reduce to smallest whole number ratio => standard equation at STP ...
3S₈ + 28Br₂ => 8S₃Br₇
Answer:
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Explanation:
