After series of conversion from one unit to another, the number of gallons was found to be 12 litres
<h3>
Density, Mass and Volume</h3>
Given Data
- Density of Sulfuric acid = 1.84 g/cm3
- Mass of Sulfuric acid = 184.33 Pounds
Conversion from pounds to Gram
1 kg ---------2.204 lb
x kg ---------184.33 lb
x = 184.33/2.204
x = 83.634 kg
hence the mass in gram = 83.634*1000
mass in gram = 83634 g
Now let us find the volume
We know that density = mass/volume
volume = mass/density
volume = 83634/1.84
volume = 45453.26 cm^3
Convert cm^3 to litres
Volume in litres = 45453.26 /1000
Volume in litres = 45.45 Litres
Convert from Litres to Gallons
1 gallon = 3.79 L
x gallons = 45.45 L
x = 45.45/3.79
x gallons = 11.99 L
Approx = 12 Litres
Learn more about density here:
brainly.com/question/1354972
Answer:
3.5 mol KClO3
Explanation:
Given 3.50 moles of KCl as the target amount in the problem, used the coefficient of the balanced chemical reaction involved to determine the number of moles of potassium perchlorate needed.
x mole of KClO3 = 3.5 mol KCl x [(2 mol KCl)/ (2 mol KClO3)] = 3.5 mol KClO3
x mole of KClO3 = 3.5 mol KClO3
Answer:
dwwq is a lot more than a lot more than a year ago and I am a very young ers and I
33rd century fox was a great place to girl and I was a little bit older than a couple of years ago and I was a little bit older than I was a little bit older than I was a little bit older than I was a little bit older than I was a little bit older than I was a little bit older than I was a little bit older than I was a little bit older than I was a little bit
Explanation:
read the full article below to see how the upper c and other factors of a child are at risk for the child or child care act and a lot 5AM in 555inches of a child is filtration of a single person who is filtration
9.75 x 10^5
A number in scientific notation has the form <em>a x 10^b</em> where
• a is the <em>coefficient</em>
• b is the <em>exponent</em>
Here are the steps to convert a number greater than 1 to scientific notation.
a) Find the coefficient
Put the decimal point after the first digit and drop the trailing zeroes
<u>9.75</u> 000
The coefficient is 9.75
.
b) Find the exponent
Count the number of digits after the first digit.
In 975 000 there are five digits after the 9. Therefore, the exponent is 5.
c) Write the number
We write 975 000 as 9.75 x 10^5.
