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skelet666 [1.2K]
3 years ago
14

Calculate the pressure in atmospheres of O2 gas at 35 degrees Celsius. It is in a .5 liter container

Chemistry
1 answer:
n200080 [17]3 years ago
8 0

Answer:

yes

Explanation:

You might be interested in
9. In a sample of gas, what causes pressure? Answer in a completesentence.
hammer [34]

Answer:

physical properties of gases, that is, pressure, volume, temperature, and amount of gas

7 0
4 years ago
Which of these substances has the lowest pH? 0.5 M HBr, pOH = 13.5 0.05 M HCl, pOH = 12.7 0.005 M KOH, pOH = 2.3
vagabundo [1.1K]
<h3><u>Answer;</u></h3>

0.5 M HBr, pOH = 13.5 ; Has the lowest pH

<h3><u>Explanation;</u></h3>

From the question;

pH = -Log [OH]

or pH = 14 - pOH

Therefore;

For 0.5 M HBr

[H+] = 0.5 M

pH = - Log [0.5]

     = 0.30

For;  pOH = 13.5

pH = 14 - pOH

     = 14 -13.5

     = 0.5

For; 0.05 M HCl

pH = - log [H+]

[H+] = 0.05

pH = - Log [0.05]

     = 1.30

For; pOH = 12.7

pH = 14 -pOH

     = 14 -12.7

     = 1.30

For;  0.005 M KOH,

pOH = - log [OH]

[OH-] = 0.005

pOH = - Log 0.005

        = 2.30

pH = 14 - 2.30

     = 11.7

For; pOH = 2.3

   pH = 14 -pOH

         = 14- 2.3

         = 11.7

6 0
3 years ago
Read 2 more answers
How many more grams should be added​
Minchanka [31]

Answer:

50?

I think but not 100% sure if not lmk

4 0
3 years ago
Calculate the molarity of 139 grams of sucrose, C12H22O11, in 2.60 liters of solution.
Allisa [31]

Answer:

to calculate the molarity of the said sucrose,

firstly calculate the moles

which is = Molecular weight of C12H22O11 = 342g/mol

then

moles = 139/342

= 0.41 moles

to calculate Molarity now

Molarity= moles of the solute/volume of solution in liter

=0.41/2.60

=0.158M

Explanation:

4 0
3 years ago
4. Ammonia is produced by the chemical reaction of nitrogen and hydrogen. N2 (g) + 3H2(g) →→ 2NH3 (9) (A) Calculate the number o
Makovka662 [10]

Answer:

a) No. of moles of hydrogen needed = 5.4 mol

b) Grams of ammonia produced = 27.2 g

Explanation:

N_2 (g)  +  3H_2(g) \rightarrow 2NH_3 (g)

a)

No. of moles of nitrogen = 1.80 mol

1 mole of nitrogen reacts with 3 moles of hydrogen

1.80 moles of nitrogen will react with

                               = 1.80 × 3 = 5.4 moles of hydrogen

b)

No. of moles of hydrogen = 2.4 mol

It is given that nitrogen is present in sufficient amount.

3 moles of hydrogen produce 2 moles of NH_3

2.4 moles of hydrogen will produce

                              = \frac{2}{3} \times 2.4 = 1.6\ mol\ of\ NH_3

Molar mass of ammonia = 17 g/mol

Mass in gram = No. of moles × Molar mass

Mass of ammonia in g = 1.6 × 17

                                    = 27.2 g

7 0
3 years ago
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