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Kryger [21]
3 years ago
7

Approximate the data using the line y = 0.25x + 3. Find the data point that has the residual with the greatest absolute value. G

ive that data point and its associated residual. Data point: (20, 6); Residual = -2.00 Data point: (15, 5); Residual = 6.75 Data point: (5, 3); Residual = -1.25 Data point: (10, 10); Residual = 4.50
Mathematics
2 answers:
ohaa [14]3 years ago
5 0

Solution: We are given data points and associated residuals:

Data Point           Residual          Absolute value(Residual)

(20,6)                     -2.00                      2.00

(15,5)                       6.75                       6.75

(5,3)                        -1.25                       1.25

(10,10)                     4.50                       4.50


From the above absolute value(Residual) column, we clearly see the data point (15,5) has the residual with greatest absolute value of 6.75.

Therefore, the data point and its associated residual is:

(15,5)  and 6.75    

Oksi-84 [34.3K]3 years ago
5 0

Answer:

Data Point: (10,10); Residual = 4.50

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Un avión puede volar con la velocidad de 400 km por hora en atmósfera tranquila si cuando se dirige hacia el este el viento vien
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Answer:

84,3 ° Sureste

Step-by-step explanation:

El diagrama vectorial que tipifica la pregunta se muestra en la imagen adjunta.

La dirección del avión es la dirección de la velocidad resultante.

Si esta dirección es θ

θ = tan ^ -1 (400/40)

θ = 84,3 ° Sureste

3 0
2 years ago
Two sets of equatic expressions are shown below in various forms: Line 1: x2 + 3x + 2 (x + 1)(x + 2) (x + 1.5)2 − 0.25 Line 2: x
kherson [118]

Answer:  The correct line is

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Step-by-step explanation:  We are given the following two sets of quadratic expressions in various forms:

\textup{Line 1: }x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25,\\\\\textup{Line 2 :}x^2+5x+6=(x+2)(x+3)=(x+2.5)^2+6.25.

We are to select one of the lines from above that represent three equivalent expressions.

We can see that there are three different forms of a quadratic expression in each of the lines:

First one is the simplified form, second is the factorised form and third one is the vertex form.

So, to check which line is correct, we need to calculate the factorised form and the vertex form from the simplified form.

We have

\textup{Line 1: }\\\\x^2+3x+2\\\\=x^2+2x+x+2\\\\=x(x+2)+1(x+2)\\\\=(x+1)(x+2),

and

x^2+3x+2\\\\=x^2+2\times x\times 1.5+(1.5)^2-(1.5)^2+2\\\\=(x+1.5)^2-2.25+2\\\\=(x+1.5)^2-0.25.

So,

\textup{Line 1 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2-0.25.

Thus, Line 1 contains three equivalent expressions.

Now,

\textup{Line 2: }\\\\x^2+5x+6\\\\=x^2+3x+2x+6\\\\=x(x+3)+2(x+3)\\\\=(x+2)(x+3),

and

x^2+5x+6\\\\=x^2+2\times x\times 2.5+(2.5)^2-(2.5)^2+6\\\\=(x+2.5)^2-6.25+6\\\\=(x+2.5)^2-0.25\neq (x+2.5)^2+6.25.

So,

\textup{Line 2 :}x^2+3x+2=(x+1)(x+2)=(x+1.5)^2+6.25.

Thus, Line 2 does not contain three equivalent expressions.

Hence, Line 1 is correct.

7 0
3 years ago
Hello i need help on it ​
sweet-ann [11.9K]

Answer:

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5 0
2 years ago
Sebastian writes the recursive formula f(x+1) = 4f(x) to represent a geometric sequence whose second term is 12.
dexar [7]
Hello,

What do you want?

a(2)=4*a(1)==>a(1)=12/4=3
a(0)=3/4

a(n)=3/4 * 4^n (genearl term)


3 0
3 years ago
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