I think is B not sure but good luck have a nice day
Answer:
The IHD = 0
There is no unsaturation in the compound C4H9Cl
Explanation:
IHD = Index for Hydrogen Deficiency .It determines total number of unsaturation or Pi- bond present in the molecule.It is calculated using the formula:
For Molecule:

Here . C = carbon
H = Hydrogen
O = Oxygen
N = Nitrogen
X = Halogen
The IHD is calculated as :
...............(1)
For example :
C4H8O2
Here c = 4 , h = 8 , o = 2 .
n = x=0
Put the value in equation (1) and find IHD



IHD = 1
For C4H9Cl
c = 4 , h = 9 and x = 1
IHD for this molecule can be calculated as :



= 0
This means there is no unsaturation in the molecule.
Each bond is sigma bond and properly saturated.
A density of a substance is constant. It is an extensive property, meaning it does not depend on the amount of substance because it is a ratio of mass to volume. No matter how much of each there is, they would always have a fixed ratio called density. For lead, the density is
Density = mass/volume
Density = 23.94 g/ 2.10 cm³
Density = 11.4 g/cm³
Answer:
pOH of resulting solution is 0.086
Explanation:
KOH and CsOH are monoacidic strong base
Number of moles of
in 375 mL of 0.88 M of KOH =
= 0.33 moles
Number of moles of
in 496 mL of 0.76 M of CsOH =
= 0.38 moles
Total volume of mixture = (375 + 496) mL = 871 mL
Total number of moles of
in mixture = (0.33 + 0.38) moles = 0.71 moles
So, concentration of
in mixture,
= 
Hence, ![pOH=-log[OH^{-}]=-log(0.82)=0.086](https://tex.z-dn.net/?f=pOH%3D-log%5BOH%5E%7B-%7D%5D%3D-log%280.82%29%3D0.086)