Answer:
1.20 M (3 s.f.)
Explanation:
In this question, we are trying to find the concentration of KCl after dilution. Note that the number of moles of KCl does not change.
Number of moles of KCl
= 44.7 ÷74.55
= 0.59960 mol (5 s.f.)
New volume
= 500 mL
= (500 ÷1000) L
= 0.5 L
Concentration after dilution
= 0.59960 ÷0.5
= 1.1992 mol/L
= 1.20 M (3 s.f.)
* M is the symbol for Molarity, which is also equal to mol/L
The heat absorbed to raise temperature : Q = 31350 J
<h3>Further explanation
</h3>
Given
m = mass = 150 g
Δt = Temperature difference : 50 °C
Required
Heat absorbed
Solution
Heat can be formulated
<em>
Q = m.c.Δt
</em>
The specific heat of water = c = 4.18 J/g °C
Input the value :
Q = 150 x 4.18 x 50
Q = 31350 J
The two parts of a solution are a Solute and the other one is a Solvent. The Solute is the substance that dissolves, and the Solvent is the majority of the solution.
Answer:
D.) Nitrogen and Hydrogen are very stable bonds compared to the bonds of ammonia.
Explanation:
For the reaction:
3H₂(g) + N₂(g) → 2NH₃(g)
The enthalpy change is ΔH = -92kJ
This enthalpy change is defined as the enthalpy of products - the enthalpy of reactants. As the enthalpy is <0, The enthalpy of products is <em>lower </em>than the enthalpy of reactants.
Also, it is possible to obtain the enthalpy change from the bond energies of products - bond energies of reactants, thus, The total bond energies of products are <em>lower</em> than the total bond energies of reactants.
The rate of the reaction couldn't be determined using ΔH.
As the bond energy of ammonia is lower than bonds of nitrogen and hydrogen, <em>D. Nitrogen and Hydrogen are very stable bonds compared to the bonds of ammonia.</em>
I hope it helps!