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ad-work [718]
3 years ago
12

The rate constant for a reaction is 4.65 L mol-1s-1. What is the overall order of the reaction? zero

Chemistry
2 answers:
il63 [147K]3 years ago
8 0

Answer:

second order

Explanation:

units of reaction and their order.

Zero order --> M^1 s^-1 = M/s

First order --> M^0 s^-1 = 1/s

Second order --> M^-1 s^-1 = L/mol s

In the question rate constant k =  4.65 L mol-1s-1. = 4.65 L/mol s

Hence, the reaction is a second order reaction

kenny6666 [7]3 years ago
5 0

Answer:

The answer is "second".

Explanation:

Given:

rate constant for a reaction = 4.65 \frac{L}{mol \cdot s}

\text{The rate of unit} =  \frac{m}{s} \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \  _{where}  \ \ M=\frac{mol}{l}   \\\\

                          =\frac{mol}{l \cdot s}

The orders                                                       unit value of the k

0                                                                               \frac{m}{s}

1                                                                                 \frac{1}{s}

2                                                                               \frac{l}{m s}

The rate of the unit is constant for the second-order that's why it is correct.

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