Answer is: formula is Al₂(CO₃)₃.
Aluminium carbonate (Al₂(CO₃)₃) has neutral charge. Because aluminium cation has positive charge 3+ and carbonate anion has negative charge 2-, for right chemical formula, we need two aluminium cations and three carbonate anion:
charge of the molecule = 2 · (3+) + 3 · (-2).
charge of the molecule = 0.
The Nassau Din beat the the star has.
It may turn into a black hole if it has a high enough mass.
I think the answer is A. Hope that helped :)
Answer: gasoline
Explanation:
An aqueous solution is one which contains water as a solvent. A non- aqueous solution is the one in which the solvent of the solution is a liquid but it is not water.
Among the options given, gasoline is the correct option. This is because of the fact that gasoline is a crude oil which does not include water as an ingredient.
Answer: 0.0 grams
Explanation:
To calculate the moles, we use the equation:

a) moles of butane

b) moles of oxygen


According to stoichiometry :
2 moles of butane require 13 moles of 
Thus 0.09 moles of butane will require =
of 
Butane is the limiting reagent as it limits the formation of product and oxygen is present in excess as (1.02-0.585)=0.435 moles will be left.
Thus all the butane will be consumed and 0.0 grams of butane will be left.