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nignag [31]
3 years ago
14

HELP!!!!!

Chemistry
1 answer:
Crank3 years ago
5 0
To get this it helps to know the electronegativity numbers of the elements but it isn't required. You just need to know that Fluorine is the most electronegative element and that the farther away from Fluorine you are on the periodic table, the less electronegative you get.  The one exception to this rule is hydrogen with actually has an electronegativity of 2.1 while lithium has one of 1.0.  Also the higher difference in electronegativity between two atoms the more polar the bond is.  

Now to start the question.  H-Br could be a contender since H has an electronegativity number of 2.1 and Br is relatively close to Fluorine so we'll put that one aside for now.  H-Cl knocks out A because both bonds have H but one bond has Br and the other has Cl.  Cl is closer to Fluorine than Br so answer B is the contender now.  For answer C, I and Br are too close to have a higher electronegativity difference than H-Cl so that one isn't it.  Finally for answer D, I is much closer to Cl than H is so the electronegativity difference is much less, making your answer B.
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Hope this helped!

Good luck :p

~Emmy <3

4 0
3 years ago
Read 2 more answers
Need answer ASAP!!!!
Keith_Richards [23]

Answer:

I am sure it is D or C. have a nice day

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Draw the alcohol that is the product of the reduction of 3-methylpentanal.
natali 33 [55]

Answer: The product from the reduction reaction is

CH3-CH2-CH(CH3)-CH2-CH2OH

IUPAC name; 3- Methylpentan-1-ol

Explanation:

Since oxidation is simply the addition of oxygen to a compound and reduction is likewise the addition of hydrogen to a compound.

Therefore, hydrogen is added onto the carbon atom adjacent to oxygen in 3- methyl pentanal

CH3 CH2 CHCH3 CH2 CHO thereby -CHO( aldehyde functional group) are reduced to CH2OH ( Primary alcohol) which gives;

3-methylpenta-1-ol .

The structure of the product is:

CH3-CH2-CH(CH3)-CH2-CH2OH

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