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alexira [117]
3 years ago
12

Equation for the complete chemical reaction, ionic equation, ionic net equation

Chemistry
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

an ionic equation is a chemical equation in which the electrolytes in aqueous solution are expressed as dissociated ions. ... Additionally, the net charge is the same on both sides of the equation.

Explanation:

So what you end up with is you always end up H+ plus OH- yields H2O, because HCl, and NaOH, since they're strong, they fully dissociate. So the Na+, and the Cl - are spectator ions. So with a strong acid and strong base, the net ion equation is always H+ plus OH- yields H2O.

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mario62 [17]
The answer is 5 gold token from Chuck E. Cheese
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Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
oee [108]
Half-life means that the matter degrades by 50% at each interval. 48.2 days is 2 intervals.

So, it would go down by 50% in the first interval, making it 50g. Then it would go down by another 50% from there, making the final amount of undecayed thorium-234 25g.
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3 years ago
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Which solute, an electrolyte or a nonelectrolyte, has the greater effect on the boiling point when a given amount of each
m_a_m_a [10]

Answer:

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Explanation:

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5 0
3 years ago
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Phosphoglucoisomerase interconverts glucose 6‑phosphate to, and from, glucose 1‑phosphate.
lawyer [7]

Answer:

Keq = 0.053

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Explanation:

Let's consider the following isomerization reaction.

glucose 6‑phosphate ⇄ glucose 1 - phosphate

The concentrations at equilibrium are:

[G6P] = 0.19 M

[G1P] = 0.01 M

The concentration equilibrium constant (Keq) is:

Keq = [G1P] / [G6P]

Keq = 0.01 / 0.19

Keq = 0.053

We can find the standard free energy change, ΔG°, of the reaction mixture using the following expression.

ΔG° = -R × T × lnKeq

ΔG° = -8.314 J/mol.K × 298 K × ln0.053

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7 0
4 years ago
Who can help me on this one ?
Bogdan [553]

Answer:

eight strong bonds to the atoms that it touches and six weaker bonds to the atoms it almost touches. This makes it easier to understand why a metal might prefer the body-centered cubic structure to the hexagonal or cubic closest-packed structure.

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