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larisa [96]
3 years ago
10

Find out how many atoms will fit in one apple . Adius of an apple is about 3.5 cm and the radius of an atom is 1.5 angstrom

Chemistry
1 answer:
e-lub [12.9K]3 years ago
6 0

Answer:

1.3 × 10²⁵ atoms

Explanation:

Step 1: Calculate the volume of an apple

The radius of an apple is 3.5 cm (3.5 × 10⁻² m). If we assume it is a sphere, we can calculate its volume using the following expression.

V = 4/3 × π × r³

V(apple) = 4/3 × π × (3.5 × 10⁻² m)³ = 1.8 × 10⁻⁴ m³

Step 2: Calculate the volume of 1 atom

The radius of 1 atom is 1.5 A (1.5 × 10⁻¹⁰ m). If we assume it is a sphere, we can calculate its volume using the following expression.

V = 4/3 × π × r³

V(atom) = 4/3 × π × (1.5 × 10⁻¹⁰ m)³ = 1.4 × 10⁻²⁹ m³

Step 3: Calculate how many atoms are in 1 apple.

V(apple)/V(atom) = 1.8 × 10⁻⁴ m³/1.4 × 10⁻²⁹ m³ = 1.3 × 10²⁵

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Question 8 (1 point)
Stells [14]

bro... come on

you better than that big bro. it literally gave u the answer

7 0
3 years ago
Which observation most likely indicates that only a chemical change has taken place
salantis [7]

The correct answer as to which observation most likely indicates that only a chemical change has taken place would that the change cannot be reversed.

When it comes to changes in a system, it can either be:

  • physical change
  • chemical change

When a substance undergoes a physical change, the original version of the substance can be recovered. In other words, physical changes can be reversible.

When a substance undergoes a chemical change, the original version cannot be recovered because an entirely new product would have been formed. In other words, chemical changes are irreversible.

Thus, once a change becomes irreversible, such a change is said to be a chemical change.

More on chemical change can be found here: brainly.com/question/1161517

4 0
2 years ago
Given 450.98 g of Cu(NO3)2, how many moles of Ag can be made? Provide your final answer rounded to two decimal places.
vivado [14]

Answer:

4.82 moles of Ag.

Explanation:

We'll begin by calculating the number of mole in 450.98 g of Cu(NO₃)₂. This can be obtained as follow:

Molar mass of Cu(NO₃)₂ = 63.5 + 2[14 + (16×3)]

= 63.5 + 2[14 + 48]

= 63.5 + 2[62]

= 63.5 + 124

= 187.5 g/mol

Mass of Cu(NO₃)₂ = 450.98 g

Mole of Cu(NO₃)₂ =?

Mole = mass /Molar mass

Mole of Cu(NO₃)₂ = 450.98 / 187.5

Mole of Cu(NO₃)₂ = 2.41 moles

Next, we shall determine the number of mole of Cu needed to produce 450.98 g (i.e 2.41 moles) of Cu(NO₃)₂. This can be obtained as follow:

Cu + 2AgNO₃ —> Cu(NO₃)₂ + 2Ag

From the balanced equation above,

1 mole of Cu reacted to produce 1 mole of Cu(NO₃)₂.

Therefore, 2.41 moles of Cu will also react to produce 2.41 moles of Cu(NO₃)₂.

Thus, 2.41 moles of Cu is needed for the reaction.

Finally, we shall determine the number of mole of Ag produced from the reaction. This can be obtained as follow:

From the balanced equation above,

1 mole of Cu reacted to produce 2 moles of Ag.

Therefore, 2.41 moles of Cu will react to produce = 2× 2.41 = 4.82 moles of Ag.

Thus, 4.82 moles of Ag were obtained from the reaction.

6 0
3 years ago
An unknown acid solution has PH 3.4. 66% of the acid is ionized. Whats the pka?
juin [17]

Answer:

pKa=3.58

Explanation:

Hello,

In this case, since the pH defines the concentration of hydrogen:

pH=-log([H^+])

[H^+]=10^{-pH}=10^{-3.4}=3.98x10^{-4}

And the percent ionization is:

\% \ ionization=\frac{[H^+]}{[HA]}*100\%

We compute the concentration of the acid, HA:

[HA]=\frac{[H^+]}{\% \ ionization}*100\%=\frac{3.98x10^{-4}}{66\%}  *100\%\\\\

[HA]=6.03x10^{-4}

Thus, the Ka is:

Ka=\frac{[H^+][A^-]}{[HA]}=\frac{3.98x10^{-4}*3.98x10^{-4}}{6.03x10^{-4}}\\  \\Ka=2.63x10^{-4}

So the pKa is:

pKa=-log(Ka)=-log(2.63x10^{-4})\\\\pKa=3.58

Regards.

5 0
3 years ago
URGENT!! Can someone please explain this to me?
djverab [1.8K]

Answer:

CH _{4}+ 2O  _{2} → CO _{2} + 2H _{2}O

for the balanced equation

from \: the \: equation \\ 1 \: mole \: of \: methane \: gives \: 1 \: mole \: of \: carbon \: dioxide \\ 7.4 \: moles \: of \: carbon \: dioxide \: will \: be \: given \: by \: (7.4 \times 1)moles \: of \: methane \\  = 7.4\: moles \: of \: methane \\  \\  since \: moles \: of \: oxygen \: double \: those \: of \: methane \\ moles \: of \: oxygen \:  = 7.4\times 2 \\  = 14.8 \: moles \: of \: oxygen

4 0
3 years ago
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