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allochka39001 [22]

3 years ago

9

What does the mode represent in a set of numbers?

2 answers:

BartSMP [9]3 years ago

4 0

Answer:

The number which appears most often in a set of numbers.

zavuch27 [327]3 years ago

3 0

Answer:

The mode is a number that appears the most in a data set

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The high school football team is playing their biggest rival this weekend. The coach has promised the team a day off practice fo

bazaltina [42]

Answer:

The independent variable is the number of touchdowns that the team scores because the number of days off of practice is dependent on the number of touchdowns that the home team scores and not the rival team.

4 0

3 years ago

likoan [24]

Answer:

are you using math solver app

6 0

3 years ago

Read 2 more answers

find a curve that passes through the point (1,-2 ) and has an arc length on the interval 2 6 given by 1 144 x^-6

taurus [48]

Answer:

$f(x) = \frac{6}{x^2} -8$ or $f(x) = -\frac{6}{x^2} + 4$

Step-by-step explanation:

Given

$(x,y) = (1,-2)$ --- Point

$\int\limits^6_2 {(1 + 144x^{-6})} \, dx$

The arc length of a function on interval [a,b]: $\int\limits^b_a {(1 + f'(x^2))} \, dx$

By comparison:

$f'(x)^2 = 144x^{-6}$

$f'(x)^2 = \frac{144}{x^6}$

Take square root of both sides

$f'(x) =\± \sqrt{\frac{144}{x^6}}$

$f'(x) = \±\frac{12}{x^3}$

Split:

$f'(x) = \frac{12}{x^3}$ or $f'(x) = -\frac{12}{x^3}$

To solve fo f(x), we make use of:

$f(x) = \int {f'(x) } \, dx$

For: $f'(x) = \frac{12}{x^3}$

$f(x) = \int {\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = \frac{12}{2x^2} + c$

$f(x) = \frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = \frac{6}{1^2} + c$

$-2 = \frac{6}{1} + c$

$-2 = 6 + c$

Make c the subject

$c = -2-6$

$c = -8$

$f(x) = \frac{6}{x^2} + c$ becomes

$f(x) = \frac{6}{x^2} -8$

For: $f'(x) = -\frac{12}{x^3}$

$f(x) = \int {-\frac{12}{x^3} } \, dx$

Integrate:

$f(x) = -\frac{12}{2x^2} + c$

$f(x) = -\frac{6}{x^2} + c$

We understand that it passes through $(x,y) = (1,-2)$ .

So, we have:

$-2 = -\frac{6}{1^2} + c$

$-2 = -\frac{6}{1} + c$

$-2 = -6 + c$

Make c the subject

$c = -2+6$

$c = 4$

$f(x) = -\frac{6}{x^2} + c$ becomes

$f(x) = -\frac{6}{x^2} + 4$

3 0

3 years ago

4(0.5f−0.25)=6+f Solve for f

Julli [10]

Answer:

F=4

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

7/8 times 1/3 times 2/5

allsm [11]

Answer:

7/60

Step-by-step explanation:

7/8 times 1/3 is 7/24.

Then, 7/24 times 2/5 is 7/60

When multiplying fractions you just multiply across. For example, 7/8 times 1/3. 7 times 1 is 7 and 8 times 3 is 24. So, 7/8 times 1/3 is 7/24.

Hope this helps :)

4 0

3 years ago