1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nesterboy [21]
3 years ago
8

What is the element Ar classified as in the periodic table?

Chemistry
2 answers:
tino4ka555 [31]3 years ago
7 0

Answer:

i believe the answer is A a noble gas

Explanation:

Ymorist [56]3 years ago
3 0
It is classified as a noble gas
You might be interested in
PLEASEEEEEEEEEEEE HELPPPPPPPP I BEGGGGG FOR HELPPPPP
Elza [17]

Answer: There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{63.00g}{18g/mol}=3.5moles

1 mole of H_2O contains =  6.023\times 10^{23} molecules

Thus 3.5 moles of H_2O contains =  \frac{6.023\times 10^{23}}{1}\times 3.5=21.08\times 10^{23} molecules.

There are 21.08\times 10^{23} molecules in 63.00 g of H_2O

3 0
3 years ago
Hi i want to know if sex cells ever develop into regular cells
mezya [45]
No, sex cells are always sex cells
8 0
2 years ago
Read 2 more answers
What is the mass of 3.55×10−2 mol Ba
scZoUnD [109]

Answer:

4.87 g

Explanation:

The formula between the number of moles, mass and Mr can be used to find the mass of barium.

<em>Number of moles = mass ÷ Mr</em>

So, mass = number of moles × Mr

  Mr of Ba = 137.3

∴ Mass = (3.55 × 10⁻²)  × 137.3 = 4.87 g

7 0
1 year ago
Molecules are not reacting using current methods. Which change can encourage a reaction?
matrenka [14]

Adding heat to a system can encourage or increases a chemical reaction.

<h3>Change that can encourage a reaction</h3>

Increasing the temperature of a process, increase occurs in the average speed of the reactant molecules and we know that when more molecules move faster, the more number of molecules reacts with other molecules which results in faster formation of products.

In conclusion, adding heat is the right option.

Learn more about reaction here: brainly.com/question/26018275

7 0
2 years ago
For a particular reaction, Δ H ∘ = 20.1 kJ/mol and Δ S ∘ = 45.9 J / (mol ⋅ K). Assuming these values change very little with tem
Sergio [31]

Answer: 438 K

Explanation:

According to Gibbs equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibb's free energy change

\Delta H = enthalpy change = 20.1 kJ/mol = 20100 J/mol

T = temperature

\Delta S = entropy change = 45.9 J/Kmol

A reaction is at equilibrium when \Delta G = Gibb's free energy change is zero and becomes spontaneous when \Delta G = Gibb's free energy change is negative.

\Delta H=T\Delta S

20100=T\times 45.9J/Kmol

T=437.9K

Thus the temperature at which the reaction change from nonspontaneous to spontaneous in the forward direction is 438 K

8 0
2 years ago
Other questions:
  • How does the photoelectric effect show that light has some properties of a stream of particles.
    10·2 answers
  • A calorimeter contains 280.0g of water at 13.5C. When 0.250g of a substance with a molar mass of 510.0g/mol is dissolved, the te
    13·1 answer
  • Provide two examples of how scientists communicate experimental results
    8·2 answers
  • Imagine that you are observing an enzyme-catalyzed reaction in lab. every time you add more enzyme, the reaction rate increases
    13·1 answer
  • Limiting Reactants—————-
    9·1 answer
  • What particles contribute to the mass of an atom?
    13·2 answers
  • Convert 2.41 x 10^2 m to cm
    11·1 answer
  • S
    8·1 answer
  • 2. what is nappening in this diagram:
    10·1 answer
  • 25. 0 ml of a 0. 100 m solution of NH3 is titrated with 0. 250m HCl. After 10. 0 ml of the hcl has been added, the resultant sol
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!