Answer:
5230J
Explanation:
Mass (m) = 250g
Initial temperature (T1) = 25°C
Final temperature (T2) = 30°C
Specific heat capacity (c) = 4.184J/g°C
Heat energy (Q) = ?
Heat energy (Q) = Mc∇T
Q = heat energy
M = mass of the substance
C = specific heat capacity
∇T = change in temperature = T2 - T1
Q = 250 × 4.184 × (30 - 25)
Q = 1046 ×5
Q = 5230J
The heat energy required to raise the temperature of 250g of water from 25°C to 30°C is 5230J
Answer:
NaNO3
Explanation:
sodium= Na
Nitrogen= N
and there's 3 oxygens = O3
We have to assume the gas behaves similar to an ideal gas and we can use the ideal gas law equation
PV = nRT
Where
P - pressure
V - volume - 7.5 L
n - number of moles - 1.0 mol
R - universal gas constant - 0.0821 L.atm/mol.K
T - temperature in kelvin
20 degrees celcius + 273 = 293 K
Substituting the values in the equation
P x 7.5 L = 1.0 mol x 0.0821 L.atm/mol.K x 293 K
P = 3.2 atm
The pressure exerted is 3.2 atm
