Question

What is the magnitude of the dipole moment formed by separating a proton and an electron by 80 pm ?

Answer 1

dipole moment is defined as product of charge and distance between between.

$P = qd$

$q = 1.6 \times 10^{-19} C$

$d = 80 pm = 80 \times 10^{-12} m$

$P = (1.6 \times 10^{-19})(80 \times 10^{-12})$

$P = 1.28 \times 10^{-29} Cm$

so above is the dipole moment of the given charges