Answer:
a) 8.4×10^-12W
b) 5.65 ×10^ -3V
c) 1.01 ×10^ -12 F
Explanation: Given:
Radius r = d/2 = 30/2=15cm= 0.15m
Maximum feild strength = Bo= 10^-12 T
Permiability of vacuum, Uo = 4pi×10^-7
I = CBo/2Uo = (3 ×10^8×(10^-12)^2)/ (4 ×3.142×10^-7)
I = 1.19×10^-10W/m^2
The intensity I = > P/A = p = IA = I(4pi^2)
P = 1.19×10^-10 × 3.142 × (0.15^2)
P = 8.4 × 10^-12W
b) Given: f = 100Mhz= 100×10^6hz
Number of turns in the coil, N = 200
Time of cycle, T = 1/f = 1/ 100×10^6
T = 10^-8 seconds
Change in t= 1/4T = 1/4×10^-8 = 2.5 ×10^-9sec
E = (N×change in B×A)/ change in t
E = (NBopir^2)/change in t
E = (200 ×10^-12× 3.142 ×(0.15^2))/ (2.5×10^-9)
E = 5.65 ×10^-3V
c) Self inductance L = 2.5UH=2.5×10^-6H
Resonant frequency, fo= 1/(2pisqrt(LC))
C= 1/(4×3.142×( 2.5×10^-6)× (100×10^6)^2
C = 1.01×10^-12F
