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Aleksandr [31]
3 years ago
9

Two teaspoons of salt are added to a glass of water which is then stirred until no more salt grains can be seen. Two more teaspo

ons are added and stirring is continued, but the salt grains are still evident in the glass and settle to the bottom. After the addition of the last two teaspoons of salt the solution is ___________________________.
nonpolar
polar
saturated
unsaturated
Chemistry
2 answers:
Naya [18.7K]3 years ago
8 0
Hello!

After the addition of the last two teaspoons of salt, the solution is saturated

A solution is saturated when it has the highest amount of solute (in this case the salt) that the solvent (in this case the water) can dissolve at that pressure and temperature. 

Visually, a saturated solution can be detected when the adding of more solute results in the settling of solute grains (in this case salt) at the bottom of the container, because the solvent couldn't dissolve them at that pressure and temperature. That's why we can say that the solution is saturated.

Have a nice day!  
Fittoniya [83]3 years ago
8 0

Answer: C

Explanation: I got it right

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anzhelika [568]
Its doesn't dissolve in water! 
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3 years ago
For Na2HPO4:(( (Note that for H3PO4, ka1= 6.9x10-3, ka2 = 6.4x10-8, ka3 = 4.8x10-13 ) a) The active anion is H2PO4- b) The activ
Komok [63]

Answer:

Check the explanation

Explanation:

Answer – Given, H_3PO_4 acid and there are three Ka values

K_{a1}=6.9x10^8, K_{a2} = 6.2X10^8, and K_{a3}=4.8X10^{13}

The transformation of H_2PO_4- (aq) to HPO_4^2-(aq)is the second dissociation, so we need to use the Ka2 = 6.2x10-8 in the Henderson-Hasselbalch equation.

Mass of KH2PO4 = 22.0 g , mass of Na2HPO4 = 32.0 g , volume = 1.00 L

First we need to calculate moles of each

Moles of KH2PO4 = 22.0 g / 136.08 g.mol-1

                             = 0.162 moles

Moles of Na2HPO4 = 32.0 g /141.96 g.mol-1

                             = 0.225 moles

[H2PO4-] = 0.162 moles / 1.00 L = 0.162 M

[HPO42-] = 0.225 moles / 1.00 L = 0.225 M

Now we need to calculate the pKa2

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       = -log 6.2x10-8

       = 7.21

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pH = pKa + log [conjugate base] / [acid]

pH = 7.21 + log 0.225 / 0.162

     = 7.35

The pH of a buffer solution obtained by dissolving 22.0 g of KH2PO4 and 32.0 g of Na2HPO4 in water and then diluting to 1.00 L is 7.35

6 0
3 years ago
If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

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Answer:

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