Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced molecular equation will be,

$BaCl_2(aq)+Li_2SO_4(aq)\rightarrow 2LiCl(aq)+BaSO_4(s)$

The complete ionic equation in separated aqueous solution will be,

$Ba^{2+}(aq)+2Cl^-(aq)+2Li^+(aq)+SO_4^{2-}(aq)\rightarrow 2Li^+(aq)+2Cl^-(aq)+BaSO_4(s)$

In this equation the species, $Li^+\text{ and }Cl^{-}$ are the spectator ions.

By removing the spectator ions , we get the net ionic equation.

The net ionic equation will be:

$Ba^{2+}(aq)+SO_4^{2-}(aq)\rightarrow BaSO_4(s)$

6 0

3 years ago

At what temperature does 0.019135 moles of Ne in a 878.3 mL container exert a pressure of 0.946 atm?

Reika [66]

<h3>Answer:</h3>

Temperature is 529.164 K

<h3>Explanation:</h3>

We are given

Number of moles of Ne (n) = 0.019135 moles

Volume (V) = 878.3 mL

Pressure (P) = 0.946 atm

We are required to calculate the temperature;

We can do this using the ideal gas law equation which is;

PV = nRT, where P is the pressure, n is the number of moles, V is the volume, R is the ideal gas constant (0.082057 Latm/mol/K) and T is the temperature.

From the equation;

$T=\frac{PV}{nR}$

$T = \frac{(0.946)(0.8783)}{(0.082057)(0.019135)}$

$T=529.164 K$

Therefore, the temperature will be 529.164 K.

5 0

3 years ago

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