Answer:
a =1 and b =2
Step-by-step explanation:
The standard quadratic is written in the form
ax^2 +bx+c =0
x^2 +2x -13 =0
a =1 and b =2
Answer:
128, -256, -1024
Step-by-step explanation:
multiply 32 by 4, multiply 128 by -2, multiply -256 by 4
The limit is the y value that the graph approaches from both sides as x approaches the target limit
it they approach different values from the left and right sides, the limit does not exist
we want to find the limit as x approaches 5
we are given that f(x)=5-x for x<5 and f(5)=8 and f(x)=x+3 for x>5
evaluate them all for f(5)
f(x)=5-x
f(5)=5-5
f(5)=0
f(5)=8
f(x)=x+3
f(5)=5+3
f(5)=8
it approaches 0 and 8 from both sides
the limit doesn't exist
D
Answer:
Explanation:Since, you have not included the formula, I will work here with the formula for
constant accelaration motion that relates the four variables:
displacement (d), Vo (initial velocity), a (acceleration) and t (time).1)
displacement formula:

2) Subtract the term Vot from both sides:

3) Multiply both sides by 2:

4) Divide both sides by t²
![2[d-V_0t]/t^2=a](https://tex.z-dn.net/?f=2%5Bd-V_0t%5D%2Ft%5E2%3Da)
So, you have obtainded:
a = 2[d - Vo×t] / t²Yet, you can arrange it in different ways. For example, you might separate into two terms: