Answer:
A horse is running at 12m/s accelerated to 38m/s in 10 seconds. What is the horses acceleration.
2.6m/s^2
Answer:
440hz
Explanation:
saxophone a plays at 430hz and a frequency of 5 beats per second can be heard so saxophone b is playing at a frequency 10hz louder than saxophone A making it 440hz
Explanation:
Given that,
A ball is tossed straight up with an initial speed of 30 m/s
We need to find the height it will go and the time it takes in the air.
At its maximum height, its final speed, v = 0 and it will move under the action of gravity. Using equation of motion :
v = u +at
Here, a = -g
v = u -gt
i.e. u = gt
![t=\dfrac{u}{g}\\\\t=\dfrac{30\ m/s}{9.8\ m/s^2}\\\\t=3.06\ s](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7Bu%7D%7Bg%7D%5C%5C%5C%5Ct%3D%5Cdfrac%7B30%5C%20m%2Fs%7D%7B9.8%5C%20m%2Fs%5E2%7D%5C%5C%5C%5Ct%3D3.06%5C%20s)
So, the time for upward motion is 3.06 seconds. It means that it will in air for 3.06×2 = 6.12 seconds
Let d is the maximum distance covered by it.
![d=ut-\dfrac{1}{2}gt^2](https://tex.z-dn.net/?f=d%3Dut-%5Cdfrac%7B1%7D%7B2%7Dgt%5E2)
Putting all values
![d=30(3.06)-\dfrac{1}{2}\times 9.8\times (3.06)^2\\\\d=45.91\ m](https://tex.z-dn.net/?f=d%3D30%283.06%29-%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%209.8%5Ctimes%20%283.06%29%5E2%5C%5C%5C%5Cd%3D45.91%5C%20m)
Hence, it will go to a height of 45.91 m and it will in the air for 6.12 seconds.