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Sergeeva-Olga [200]
3 years ago
15

4. Challenge: Try to explain these results based on the fact that air pressure decreases with

Physics
1 answer:
lara [203]3 years ago
6 0

Answer with Explanation:

<em>I can see that you haven't attached the results.</em>

Under Ideal Gas Law, "pressure" is<u> directly proportional to the number of molecules</u> (provided that the volume and temperature remains constant).

Most of the atmosphere's molecules are drawn towards the surface of the Earth because of "gravity." This means that there are <u>more atmospheric molecules closer to the Earth's surface,</u> which also means the air pressure in lower altitude is higher due to a denser air space.

This, in turn, leaves a <u>lesser number of atmospheric molecules as the height increases</u> which means there is lesser atmospheric pressure in areas of higher altitudes due to a less denser air space.

So, this explains the answer.

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Answer:

0.823 Nm

Explanation:

current, i = 100 A

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Magnetic field, B = 0.524 T

Torque is defined as the

\tau = i \times A\ B\times sin\theta

\tau = 100 \times 3.14\times 0.1\times 0.1\ 0.524\times 0.5

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An airplane starts at rest and accelerates at 6.8 m/s2 at an angle of 39° south of west. After 9 s, how far in the westerly dire
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The most recently discovered system close to Earth is a pair of brown dwarfs known as Luhman 16. It has a distance of 6.5 light-
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Answer:

1.99 parsecs.

Explanation:

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We know that one light year equals to 0.306601 parsecs. To convert 6.5 light-years to parsecs, we will multiply 0.306601 by 6.5.

6.5\text{ Light-years}=6.5\times 0.306601\text{ Parsecs}

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You are throwing a stone straight-up in the absence of air friction. The stone is caught at the same height from which it was th
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Answer:

A. True

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When a stone is thrown straight-up, it has an initial velocity which decreases gradually as the stone move to maximum height due to constant acceleration due to gravity acting downward on the stone, at the maximum height the final velocity of the stone is zero. As the stone descends the velocity starts to increase and becomes maximum  before it hits the ground.

Height of the motion is given by;

H = \frac{u^2}{2g}

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