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2 years ago

7

Sonam and Wangchuk are taking part in a long jump event during their school's annual sports day. Sonam ran a few distances befor

e taking the jump while Wangchuk jumped without running. Who will jump furthest? Justify your answer.

1 answer:

puteri [66]2 years ago

8 0

Answer:

Sonam will jump further than wangchuck

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A car traveled 60 km in 2 hours,84 km in the next 1 hour, and then 68 km in 2 hours before reaching its destination. What was th

zhenek [66]

60+84+68 / 5 = 42.4 km/hr

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3 years ago

A ball thrown straight up takes 1.89s to reach a height of 41.6m.

yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

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3 years ago

. The free throw line in basketball is 4.57 m (15 ft) from the basket, which is 3.05 m (10 ft) above the floor. A player standin

pentagon [3]

Answer:

$\theta = 67.22 degree$

Explanation:

Let say the ball is projected at an angle with horizontal

So here two components of the velocity of the ball is given as

$v_x = 8.15 cos\theta$

$v_y = 8.15 sin\theta$

now the displacement in x direction is given as

$x = v_x t$

$4.57 = (8.15 cos\theta)t$

in y direction it is given as

$y = y_o + v_y t - \frac{1}{2}gt^2$

$3.05 = 2.44 + (8.15 sin\theta) t - 4.9 t^2$

now from above two equations

$0.61 = 4.57 tan\theta - 4.9(\frac{4.57}{8.15 cos\theta})^2$

$0.61 = 4.57 tan\theta - 1.54(1 + tan^2\theta)$

$1.54 tan^2\theta - 4.57 tan\theta + 2.15 = 0$

$\theta = 67.22 degree$

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3 years ago

4.-Una atleta patea un balon (masa de 650gr y angulo de 45 grados) arriba de un edificio con una velcidad 21 m/s, el edificio mi

marta [7]

Answer:

v = 25 m/s

Explanation:

½mv₀² + mgh = ½mv₁²

v₁² = v₀² + 2gh

v₁ = √(21² + 2(9.8)(10))

v₁ = 25.238858..

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3 years ago

A passenger jet flies from one airport to another 1,273 miles away in 2.2 h. find its average speed.

oee [108]

Speed : distance divide by time . 1273/2.2 = ...

Use calculator .

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3 years ago

Read 2 more answers