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marishachu [46]

2 years ago

8

A person jumps from a plane in is falling the person releases a parish you in continues to fall the person lays 35.2 kg and ther

e is a driving force of 45N what is the net for acting on the person

1 answer:

irakobra [83]2 years ago

7 0

Answer:

cookie

Explanation:

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2 years ago

A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t

kykrilka [37]

Explanation:

It is given that,

Mas of the car, $m_1=1170\ kg$

Initial speed of the car, $u_1=25\ m/s$

Mass of the truck, $m_2=9800\ kg$

Initial speed of the car, $u_2=20\ m/s$

Final speed of the car, $v_1=18\ m/s$

(a) It is a case of elastic collision. Let $v_2$ is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$

$v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}$

$v_2=\dfrac{1170\times 25+9800\times 20-1170\times 18}{9800}$

$v_2=20.83\ m/s$

(b) Initial kinetic energy is given by :

$k_i=\dfrac{1}{2}(m_1u_1^2+m_2u_2^2)$

$k_i=\dfrac{1}{2}\times (1170\times (25)^2+9800\times (20)^2)$

$k_i=2325625\ J$

Final kinetic energy is given by :

$k_f=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)$

$k_f=\dfrac{1}{2}\times (1170\times (18)^2+9800\times (20.83)^2)$

$k_f=2315595.61\ J$

The change in mechanical energy of the car truck system in the collision:

$\Delta K=k_f-k_i$

$\Delta K=2315595.61-2325625$

$\Delta k=-10029.39\ J$

The loss in kinetic energy is 10029.39 Joules.

(c) The change in mechanical energy gets changed energy gets changed in the form of heat and light.

Hence, this is the required solution.

6 0

2 years ago