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Rzqust [24]
3 years ago
13

Which of the following changes will likely increase the solubility of a solid solute but decrease the solubility of a gaseous so

lute? A. Increasing the molecular mass of the solute B. Increasing the temperature C. Decreasing the concentration D. Decreasing the atmospheric pressure
Chemistry
2 answers:
Readme [11.4K]3 years ago
6 0
A. Increasing the molecular mass of the solute, Because that would Increase the solubility of solid solute, but wouldn't increase the gaseous solute.
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MA_775_DIABLO [31]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

When we increase the temperature then there is increase in solubility of a solid because of more number of collisions between its particles. As a result, there will be an increase in rate of reaction.

But when we increase the temperature for a gaseous solute then its molecules will gain more kinetic energy due to which they collide more rapidly. Hence, they will escape out of the reaction mixture so, there will be decrease in the solubility of a gaseous solute.

Thus, we can conclude that increasing the temperature will most likely increase the solubility of a solid solute but decrease the solubility of a gaseous solute.

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A sealed vessel contains 0.200 mol of oxygen gas, 0.100 mol of nitrogen gas, and 0.200 mol of argon gas. The total pressure of t
babunello [35]

Answer:

D

Explanation:

We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles

Now, we know that the mole fraction of the argon gas would be 0.2/0.5

The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.

0.2/0.5 * 5 = 1.0/0.5 = 2.00atm

D

8 0
3 years ago
What product(s) are expected in the ethoxide-promoted β-elimination reaction of 2-bromo-2,3-dimethylbutane? Omit ions, salts, an
Sidana [21]
There are two possible products from this elimination: 
-2,3-dimethylbut-1-ene 
-2,3-dimethylbut-2-ene 

As the base is relatively unhindered, the reaction will form the Saytzeff product as the major product. The Saytzeff product is the most substituted alkene which is more stable due to hyperconjugation. In this reaction the Saytzeff product is 2,3-dimethylbut-2-ene.
4 0
4 years ago
What happens when an electron moves from a higher energy level to a lower one
hjlf
When an electron moves from a higher to a lower energy level, energy is released (often as light).
4 0
4 years ago
Help me please i don’t understand the problem
brilliants [131]

Answer:

Atoms are neither created or destroyed.

Explanation:

The end result of a chemical change does not create or destroy any atoms. Matter cannot be created or destroyed, meaning the same amount of atoms exist before and after the change.

5 0
4 years ago
Read 2 more answers
If the azeotropic mixture is 72% perchloric acid by mass, what is the mole percent of water in the azeotrope?
WARRIOR [948]

Answer:

Mole percent of water in azeotrope is 69%

Explanation:

Clearly, the azeotrope consists of water and perchloric acid.

So, 72% perchloric acid by mass means 100 g of azeotrope contains 72 g of perchloric acid and 28 g of water.

Molar mass of water = 18.02 g/mol and molar mass of perchloric acid = 100.46 g/mol

So, 72 g of perchloric acid = \frac{72}{100.46}mol of perchloric acid = 0.72 mol of perchloric acid

Also, 28 g of water = \frac{28}{18.02}mol of water = 1.6 mol of water

Hence total number of mol in azeotrope = (1.6+0.72) mol = 2.32 mol of azeotrope

So, mole percent of water in azeotrope = [(moles of water)/(total no of moles)]\times 100%

Mole percent of water  = \frac{1.6}{2.32}\times 100 % = 69%

3 0
4 years ago
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