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Rzqust [24]
3 years ago
13

Which of the following changes will likely increase the solubility of a solid solute but decrease the solubility of a gaseous so

lute? A. Increasing the molecular mass of the solute B. Increasing the temperature C. Decreasing the concentration D. Decreasing the atmospheric pressure
Chemistry
2 answers:
Readme [11.4K]3 years ago
6 0
A. Increasing the molecular mass of the solute, Because that would Increase the solubility of solid solute, but wouldn't increase the gaseous solute.
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MA_775_DIABLO [31]3 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

When we increase the temperature then there is increase in solubility of a solid because of more number of collisions between its particles. As a result, there will be an increase in rate of reaction.

But when we increase the temperature for a gaseous solute then its molecules will gain more kinetic energy due to which they collide more rapidly. Hence, they will escape out of the reaction mixture so, there will be decrease in the solubility of a gaseous solute.

Thus, we can conclude that increasing the temperature will most likely increase the solubility of a solid solute but decrease the solubility of a gaseous solute.

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For the main group elements( excluding the transition elements) , is it necessary to memorize the type of ion each element makes
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You can predict it based of the electronegativity
7 0
3 years ago
Select correct examples of linear molecules for five electron groups. Select correct examples of linear molecules for five elect
Shalnov [3]

Explanation:

Formula to calculate hybridization is as follows.

                Hybridization = \frac{1}{2}[V+N-C+A]

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

So, hybridization of BeCl_{2} is as follows.

              Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[2 + 2]

                                    = 2

Hybridization of BeCl_{2} is sp. Therefore, BeCl_{2} is a linear molecule. There will be only two electron groups through which Be is attached.

Similarly, hybridization of XeF_{2} is calculated as follows.

         Hybridization = \frac{1}{2}[V + N - C + A]

                                    = \frac{1}{2}[8 + 2]

                                    = 5

Therefore, hybridization of XeF_{2} is sp^{3}d. Therefore, [tex]XeF_{2} is also a linear molecule. Though there are three lone pair of electrons present on a xenon atom and it is further attached with fluorine atoms through two electron pairs. Hence, there are in total five electron groups.

Thus, we can conclude that out of the given options XeF_{2} is the correct examples of linear molecules for five electron groups.

7 0
3 years ago
Will a horse galloping in a field produce and average velocity of zero
motikmotik

Answer:

No

Explanation:

Depending on the mass of the horse and the speed, velocity will change.

5 0
3 years ago
Please help on 8 thank youuuuuuuuuu
enyata [817]

Answer:

b)5l x 10kg  c)10kg + 9l   (Not sure for the last 1)

6 0
3 years ago
According to kinetic-molecular theory, which of the following would not be considered an ideal gas? Check all that apply.
Vikki [24]

Answer:

are a gas at very low volumes, when gas particles are very close together

a gas at very low temperatures, when gas particles have very little kinetic energy

a gas with highly polar molecules that have very strong intermolecular forces

Explanation:

4 0
3 years ago
Read 2 more answers
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