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Rzqust [24]
2 years ago
13

Which of the following changes will likely increase the solubility of a solid solute but decrease the solubility of a gaseous so

lute? A. Increasing the molecular mass of the solute B. Increasing the temperature C. Decreasing the concentration D. Decreasing the atmospheric pressure
Chemistry
2 answers:
Readme [11.4K]2 years ago
6 0
A. Increasing the molecular mass of the solute, Because that would Increase the solubility of solid solute, but wouldn't increase the gaseous solute.
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MA_775_DIABLO [31]2 years ago
5 0

Answer: Option (B) is the correct answer.

Explanation:

When we increase the temperature then there is increase in solubility of a solid because of more number of collisions between its particles. As a result, there will be an increase in rate of reaction.

But when we increase the temperature for a gaseous solute then its molecules will gain more kinetic energy due to which they collide more rapidly. Hence, they will escape out of the reaction mixture so, there will be decrease in the solubility of a gaseous solute.

Thus, we can conclude that increasing the temperature will most likely increase the solubility of a solid solute but decrease the solubility of a gaseous solute.

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____________ is a point source of water pollution; _____________ is a nonpoint source of water pollution.
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How many moles of oxygen are necessary to react completely with four moles of propane (CH)?
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7 0
3 years ago
The reaction for photosynthesis producing glucose sugar and oxygen gas is:
Anvisha [2.4K]

<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

  • CO₂: 6 moles
  • H₂O: 6 moles
  • C₆H₁₂O₆: 1 mole
  • O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

5 0
3 years ago
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