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TEA [102]
3 years ago
5

The inhabitants of a planet in another galaxy have their eyes at the exact center of their 4.0-m-long bodies. How long must a pl

ane mirror be for such a creature to be able to see all of its body in the mirror
Physics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

The correct answer will be "2 m".

Explanation:

As we know,

⇒  \frac{Mirror's \ size}{Body's \ height} =\frac{1}{2}

Now,

⇒  Size \ of \ a \ mirror = \frac{n}{2}

Then,

⇒  Size \ of \ mirror = \frac{4}{2}

⇒                            =2 \  meter

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A horizontal force acts on an object on a fric- tionless horizontal surface. If the force is halved and the mass of the object i
guapka [62]

(a)  If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)  if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

The force on an object is determined by applying Newton's second law of motion;

F = ma

\frac{F_1}{m_1a_1} = \frac{F_2}{m_2a_2}

(a)

when the force is halved, F₂ = 0.5F₁,

mass is doubled, m₂ = 2m₁

\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)

Thus, if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

Learn more here:brainly.com/question/19887955

3 0
3 years ago
A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec
olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

h=u't+\dfrac{1}{2}gt^2

h=\dfrac{1}{2}gt^2

h=\dfrac{1}{2}\times 9.8\times (4.3)^2

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0
3 years ago
The total amount of kinetic energy and potential energy within a system is called Question 4 options: A. thermal energy B.electr
dolphi86 [110]
I'm pretty sure the answer is C. :)
5 0
3 years ago
Plz do all of it i will give brainlest and thanks to best answer<br> plz do it right
AlladinOne [14]
The answer is a rainforest I’m pretty sure
3 0
3 years ago
Read 2 more answers
Is Mercury a heavier element than tin
Kryger [21]
Yes because mercury has more protons and electrons that tin. (30 more)
4 0
3 years ago
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