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yan [13]
3 years ago
7

What is a correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9?

Physics
1 answer:
lora16 [44]3 years ago
3 0
<h3>Solution:</h3>

firstly solve parenthesis bracket ( )

-4×3 + 4×5x ≥ -6x + 9

-12 + 20x ≥ -6x + 9

Add 12 on both sides

-12 + 12 + 20x ≥ -6x + 9 + 12

20x ≥ -6x + 21

Add 6x on both sides

6x+ 20x ≥ -6x + 6x + 21

26x ≥  21

divide both side by 26

26 x/26 ≥21/26

x ≥21/26

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Answer:b) atoms

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3 years ago
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a painting in an art gallery has height h and is hung so that its lower edge is a distance d above the eye of an observer. How f
harkovskaia [24]

Solution:

With reference to Fig. 1

Let 'x' be the distance from the wall

Then for \DeltaDAC:

tan\theta = \frac{d}{x}

⇒ \theta = tan^{-1} \frac{d}{x}

Now for the \DeltaBAC:

tan\theta = \frac{d + h}{x}

⇒ \theta = tan^{-1} \frac{d + h}{x}

Now, differentiating w.r.t x:

\frac{d\theta }{dx} = \frac{d}{dx}[tan^{-1} \frac{d + h}{x} -  tan^{-1} \frac{d}{x}]

For maximum angle, \frac{d\theta }{dx} = 0

Now,

0 = [/tex]\frac{d}{dx}[tan^{-1} \frac{d + h}{x} -  tan^{-1} \frac{d}{x}][/tex]

0 = \frac{-(d + h)}{(d + h)^{2} + x^{2}} -\frac{-d}{x^{2} + d^{2}}

\frac{-(d + h)}{(d + h)^{2} + x^{2}} = \frac{{d}{x^{2} + d^{2}}

After solving the above eqn, we get

x = \sqrt{\frac{d}{d + h}}

The observer should stand at a distance equal to x = \sqrt{\frac{d}{d + h}}

4 0
3 years ago
An object on Earth weighs 150 N. What is its mass?
Alex777 [14]

Answer:

\tt \: mass \:  =  \frac{weight}{acceleration \: due \: to \: gravity}

\longrightarrow \tt \:  \frac{150}{10}

\longrightarrow \boxed{ \tt{15 \: kg}}

  • Our final answer is 15 kg .

----------- HappY LearninG<3 ------------

3 0
2 years ago
Identify characteristics of energy from the Sun. Check all that apply.
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Almost all of the energy on Earth comes from the Sun

The energy in fossil fuels originally came from the Sun

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  • Almost all of the energy on earth comes from the sun. A few component of the energy on the surface comes from the internal heat engine.
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6 0
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Answer:

Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region

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Charge-coupled device  (CCD) is a device that receives and transfers an electrical charge to the next region where it can be modified like changing it to a electronic value.

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