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mariarad [96]
3 years ago
10

The formula d = t² + 5 t expresses a car's distance (in feet) from a stop sign, d, in terms of the number of seconds t since it

started moving.
Determine the car's average speed over the interval of time from t = 4 seconds to t = 7 seconds.
Physics
1 answer:
Lubov Fominskaja [6]3 years ago
3 0

Answer:

The car's average speed is 16 feet per second.

Explanation:

The expression for the average speed is as follows;

A.S=\frac{\textrm{Total distance}}{\textrm{total time}}

Given expression of distance:

d=t^{2}+5t

Put t= 4 s.

d(4)=(4)^{2}+5(4)

d(4)= 36 ft

Put t= 7 s in the given expression.

d(7)=(7)^{2}+5(7)

d(7)= 84 ft

Calculate the car's average speed over the interval of time from t = 4 seconds to t = 7 seconds.

A.S=\frac{d(7)-d(4)}{7-4}

A.S=\frac{84-36}{7-4}

A.S= 16 feet per second

Therefore, the car's average speed is 16 feet per second.

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Answer:

Velocity=6.03m/s

Explanation:

Given data

Time t=2.5 minutes=150 seconds

Distance A=1600 ft=487.68 m........east

Distance B=2500 ft=762m ........north

To find

Average velocity

Solution

First we need to find the resultant distance magnitude.To find that we apply Pythagorean theorem to find hypotenuse

So

A^{2}+B^{2}=C^{2}\\  C=\sqrt{A^{2}+B^{2}}\\ C=\sqrt{(487.68m)^{2}+(762m)^{2}}\\ C=904.7m

Velocity=\frac{Distance}{Time}\\Velocity=\frac{904.7m}{150s}\\Velocity=6.03m/s

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Which of the following statements about the conservation of momentum is not correct? Momentum is conserved for a system of objec
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Answer:

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A bicycle is ridden along a horizontal road with a driving force of 400, n,400n. its speed is constant at 12, m, slash, s,12m/s.
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The magnitude of the sum of the frictional forces acting on the bike and its rider is 400N.

<h3>What is friction force?</h3>

The friction force is the opposing force which acts on the object which is in relative motion.

The driving force is equal and opposite to the friction force acting between road and bicycle.

Friction force = 400N

The friction force between rider and bike is zero.

So the magnitude of sum of friction force = 400N +0 = 400N

Thus, the magnitude of the sum of the frictional forces acting on the bike and its rider.

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