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ANEK [815]
3 years ago
11

What is a major division between gravity and the electromagnetic force on one hand and the nuclear forces on the other?

Physics
1 answer:
alekssr [168]3 years ago
6 0

Answer:

1) Gravity and the electromagnetic force have infinite ranges while the nuclear forces have very small ranges.

Explanation:

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Read 2 more answers
A tennis player tosses a tennis ball straight up and then catches it after 2.00 s at the same height as the point of release. (a
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Answer:

Part a)

a = -9.81 m/s/s

Part b)

v = 0

Part c)

v = 9.81 m/s

Part d)

H = 4.905 m

Explanation:

Part a)

During the motion of ball it will have only gravitational force on the ball

so here the acceleration of the ball is only due to gravity

so it is given as

a = g = 9.81 m/s^2

Part b)

As we know that ball is moving against the gravity

so here the velocity of ball will keep on decreasing as the ball moves upwards

so at the highest point of the motion of the ball the speed of ball reduce to zero

v_f = 0

Part c)

We know that the total time taken by the ball to come back to the initial position is T = 2 s

so in this time displacement of the ball will be zero

\Delta y = 0 = v_y t + \frac{1}{2} at^2

0 = v_y (2) - \frac{1}{2}(9.81)(2^2)

v_y = 9.81 m/s

Part d)

at the maximum height position we know that the final speed will be zero

so we will have

v_f^2 - v_i^2 = 2 a d

here we have

0 - (9.81^2) = 2(-9.81)H

H = 4.905 m

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3 years ago
A ball accelerates from rest down a ramp at 2.4 m/s^2. Write an equation that could be used to determine the balls finals positi
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Answer:

x=2.4t+4.9t^2

Explanation:

This equation is one of the kinematic equations to solve for distance. The original equation is as follows:

X=Xo+Vt+1/2at^2

We know that the ball starts at rest meaning that its initial velocity and position is zero.

X=0+Vt+1/2at^2

Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.

X=Vt+4.9t^2

Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.

Now, substitute in your velocity value.

X=2.4t+4.9t^2

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