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crimeas [40]
3 years ago
12

A dog whistle is designed to produce a sound with a frequency beyond that which can be heard by humans (between 20,000 Hz and 27

,000 Hz). If a particular whistle produces a sound with a frequency of 25,000 Hz, what is the sound’s speed? Assume the wavelength of this sound wave in air is 0.013m. *
4 points
325 m/s
250 m/s
113 m/s
467 m/s
Physics
1 answer:
Viktor [21]3 years ago
7 0

Answer:

Speed of the sound in air is 325 m/s

Explanation:

As we know that the frequency of the sound is given as

f = 25000 Hz

wavelength of the sound is given as

\lambda = 0.013 m

now we have

v = \lambda f

so we have

v = (0.013)(25000)

v = 325 m/s

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In a single-slit diffraction experiment, the slit is 0.1mm wide and is illuminatedby monochromatic light with a wavelength of 50
dem82 [27]

Answer:

0.1 m

Explanation:

d = slit width = 0.1 mm = 0.1 x 10⁻³ m

\lambda = wavelength of monochromatic light = 500 nm = 500 x 10⁻⁹ m

D = Distance of the screen = 10 m

w = Spacing between successive minima

Spacing between successive minima is given as

w = \frac{2D\lambda }{d}

Inserting the values given

w = \frac{2(10)(500\times10^{-9}) }{0.1\times10^{-3}}

w = 0.1 m

4 0
3 years ago
ANSWER PLS!!<br><br> In two to three sentences, differentiate between a motor and a generator
Degger [83]

-- A motor and a generator both do a transformation between electrical energy and some other form of energy, but they do it in opposite directions.

-- A motor takes electrical energy and transforms it into mechanical energy, which can then be used to run mechanical things like cars or wheat grinders.

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8 0
3 years ago
Consider a neutron star of radius 10 km that spins with a period of 0.8 seconds. Imagine a person is standing at the equator of
Arada [10]

Answer:

a = 616850.28 m/s²

Explanation:

Given that,

The radius of the neutron star, r = 10 Km

                                                     = 10,000 m

The time period of the neutron star, T = 0.8 s

The centripetal acceleration is given by the formula,

                                  a = v²/r

The linear velocity is given by the relation,

                                    v = rω

The time taken to complete one complete rotation is given by the relation

                                   T = 2π /ω

Where,

                                    ω = 2π / T

Substituting v and ω into the equation for centripetal acceleration. It becomes

                                    a = 4π²r/T²

Substituting the given values in the above equation

                                      a = 4π² x 10000 / 0.8²

                                         = 616850.28 m/s²

Hence, the centripetal acceleration of this person is, a = 616850.28 m/s²

8 0
3 years ago
a sound wave travels at 330 m/sec and has a wavelenght of 2meters. calcuate the frequency and period
Sergio039 [100]

The frequency of any wave is  (speed) / (wavelength).

 Frequency = (330 m/s) / (2m)  =  165 per second = <em>165 Hz</em>.

Period = 1 / frequency  =  1 / (165 per second) = <em>0.0061 second </em>


7 0
3 years ago
A book is sitting on a table. The book is
Sav [38]

Answer:

65 Newtons

Explanation:

4 0
3 years ago
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