Question

11 grams of carbon dioxide, CO2, is dissolved in 1000 mL of solution. Determine the molarity (M).​

Answer 1

Answer: The molarity is 0.25 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in ml

moles of $CO_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{11g}{44g/mol}=0.25mol$

Now put all the given values in the formula of molality, we get

$Molarity=\frac{0.25\times 1000}{1000ml}$

$Molarity=0.25M$

Therefore, the molarity is 0.25 M