A newspaper and a metal lunchbox are sitting in sun. Why does metal lunchbox feel hotter to touch than a newspaper?

Help please with question 2bii The one that starts with calculate the average ....

Anna11 [10]

Answer:

add text fully or atleast add book name edition . solution is in picture. chk pictures ignore b part

Explanation:

4 0

3 years ago

About 65 million years ago an asteroid struck Earth in the area of the Yucatán Peninsula and wiped out the dinosaurs and many ot

9966 [12]

Answer:

$2.44156\times 10^{13}\ m^3$

29010.53917 m

Explanation:

$\rho$ = Density of asteroid = 2 g/cm³

V = Volume

d = Diameter = 10 km

r = Radius = $\dfrac{d}{2}=\dfrac{10}{2}=5\ km$

v = Velocity = 11 km/s

$H_v$ = Heat vaporization of water = $2.26\times 10^6\ J/kg$

$\Delta T$ = Change in temperature = 100-20

Mass is given by

$m=\rho V\\\Rightarrow m=\rho\dfrac{4}{3}\pi r^3\\\Rightarrow m=2000\dfrac{4}{3}\times \pi\times 5000^3\\\Rightarrow m=1.0472\times 10^{15}\ kg$

The kinetic energy is

$K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}1.0472\times 10^{15}\times 11000^2\\\Rightarrow K=6.33556\times 10^{22}\ J$

Heat is given by

$Q=mc\Delta T+mH_v\\\Rightarrow 6.33556\times 10^{22}=m\times (4186\times (100-20)+2.26\times 10^6)\\\Rightarrow m=\dfrac{ 6.33556\times 10^{22}}{4186\times (100-20)+2.26\times 10^6}\\\Rightarrow m=2.44156\times 10^{16}\ kg$

Mass of water is $2.44156\times 10^{16}\ kg$

Volume is $\dfrac{2.44156\times 10^{16}}{10^3}=2.44156\times 10^{13}\ m^3$

Amount of water is $2.44156\times 10^{13}\ m^3$

If it were a cube

$h=V^{\dfrac{1}{3}}\\\Rightarrow h=(2.44156\times 10^{13})^{\dfrac{1}{3}}\\\Rightarrow h=29010.53917\ m$

The height of the water would be 29010.53917 m

4 0

3 years ago

Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. drag each item to the a

horrorfan [7]

Three of these are strong electrolytes:
- HCl (Hydrochloric acid)
- HNO3 (Nitric acid)
- NaOH (Sodium hydroxide)

Two of these are Weak electrolytes:
- HF (Hydrogen fluoride)
- HC2H3O2 (Acetic acid)

And the other two are Non-electrolytes:
- C6H12O6 (Glucose)
- C2H5OH (Ethanol)

4 0

3 years ago

Read 2 more answers

A series ac circuit contains a resistor, an inductor of 150 mh, a capacitor of 5.00 m f , and a source with vmax = 240 v operati

antoniya [11.8K]

Ω=2*pi*f = 2*pi*50 = 314.16

Inductive reactance, ZL = jωL = j*314.16*0.15 = j42.12
Capacitance reactance, ZC = 1/(jωC) =1/(j*314.16*0.005) = -j0.64
Impendance, Z = V/I = 240/0.1 = 2400

Now,
Z=R+j(ZL+ZC) => 2400 = R+ j(45.12-0.64) => 2400 = R + j44.48
Additionally,
2400^2 = R^2+44.48^2 => R = Sqrt (2400^2-44.48^2) = 2399.58 ohms.

Phase angle = arctan (44.48/2399.58) = 1.06°

4 0

3 years ago

17. Suppose you attach the object with mass m to a vertical spring originally at rest, and let it bounce up and down. You releas

insens350 [35]

Answer:

See below ↓

Explanation:

Step 1 : Diagram

In attachment

Step 2

We choose the system to be the spring, the block, and the Earth and it is isolated
We put all the data in the figure we have created and create a zero level (initial height) of the block to be yₓ = 0 and the final position, when it stops and moves upwards again, to be yₙ = -A
No external forces are exerted on the system and no energy comes in or out of the system
Hence,

⇒ ΔE = 0

⇒ Eₙ - Eₓ = 0

⇒ Eₙ = Eₓ

⇒ Kₙ + Uₙ + Pₙ = Kₓ + Uₓ + Pₓ

Final kinetic energy is 0 at the lowest point

⇒ Uₙ + Pₙ = Uₓ + Pₓ

Step 3

Initial potential energy is 0 [zero level = initial height]

⇒ Uₙ + Pₙ = Uₓ

And we know that spring was originally at normal length, so initial spring energy is also 0

⇒ Uₙ + Pₙ = 0

⇒ 1/2kxₙ² + mgyₙ = 0

⇒ 1/2kxₙ² = -mgyₙ

We know xₙ = A and yₙ = -A from the diagram

⇒ 1/2kA² = -mg(-A)

⇒ 1/2kA² = mgA

⇒ [1/2kA = mg]

Step 4

Spring force is given by : F = -kx
Note : x = A

⇒ F = kA

⇒ k = F/A

⇒ Plug 'k' into the equation found at the end of Step 3

⇒ 1/2(F/A)(A) = mg

⇒ 2F = mg

⇒ F = 2mg (a)

Step 5

We know the spring will stop oscillating and be at rest at the new equilibrium position of the system

⇒ F - mg = 0

⇒ F = mg

We know that :

⇒ F = -kx

In the case x = yₙ

⇒ kyₙ = mg

⇒ yₙ = mg/k

⇒ yₙ = 0.25 x 9.8 / -10

⇒ yₙ = -0.245 m

⇒ yₙ = A

⇒ yₙ = 0.245 m (b)

Step 6

v(max) = Aω
v(max) = A√k/m
v(max) = 0.245 x √(10/0.25)
v(max) = 1.55 m/s (c)

8 0

2 years ago