A bird cab fly 25km/h how long does it take to fly 3.5km

A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum heigh

Nana76 [90]

Answer:

The maximum height reached by the ball is 2.84 m

Explanation:

Given;

initial velocity of the soccer, u = 13 m/s

angle of projection, θ = 35°

The maximum height reached by the ball = ?

Apply the following kinematic equation, to determine the maximum height reached by the ball.

Maximum height (H) is given as;

$H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m$

Therefore, the maximum height reached by the ball is 2.84 m

3 0

3 years ago

Acceleration is defined as a change in velocity over time. If a runner increases velocity

Anton [14]

Answer:

a = 0,1[m/s^2]

Explanation:

First we need to indentify the initial data.

And using this kinematic equation we have:

$v = 4[m/s]\\v_{0}= 2 [m/s] \\t = 20[s]\\\\v= v_{0}+a*t\\a=\frac{v-v_{0}}{t} \\a= \frac{4-2}{20} \\a=0.1[m/s^{2}]$

8 0

4 years ago

Determine the average velocity and average speed for the following situation. A dog runs west for 35 meters then turns east for

mart [117]

Answer:

0.882 m/s average velocity and 1.71 m/s average speed

Explanation:

The dog travels a total of 35 m west and 110 m east.

110-35 = 75 m east of the starting position. Since velocity is a vector you must consider its first and final position and not the total distance traveled.

75 m / 85 s = 0.882 m/s average velocity

Speed is not concerned with direction so we instead add the total distance traveled which is 35+110 = 145 m. We then perform the same operation as before and divide by the time it took to run this distance.

145 m / 85 s = 1.71 m/s average speed

7 0

3 years ago

A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s. Assuming the diameter of a tire is 58.0 cm, (a)

Virty [35]

Answer:

Explanation:

Given:

Initial velocity, u = 0 m/s (at rest)

Final velocity, v = 22 m/s

Time, t = 9 s

Diameter, d = 58 cm

Radius, r = 0.29 m

Using equation of motion,

v = u + at

a = (22 - 0)/9

= 2.44 m/s^2

v^2 = u^2 + 2a × S

S = (22^2 - 0^2)/2 × 2.44

= 99.02 m

S = r × theta

Theta = 99.02/0.29

= 341.44 °

1 rev = 360°

341.44°,

= 341.44/360

= 0.948 rev

= 0.95 rev

B.

Final angular speed, wf = v/r

= 22/0.29

= 75.86 rad/s

6 0

3 years ago

A car of mass 2400kg accelerates from 10m/s to 30m/s if the force is 12000N what is the distance

leonid [27]

Explanation:

Initial velocity (u) = 10 m/s
Final velocity (v) = 30 m/s
Mass (m) = 2400 kg
Force (F) = 12000 N

Let us find the time taken first.

→ F = ma

Acceleration (a) = (v – u)/t

→ 12000 = 2400 × (30 – 10)/t

→ 12000 ÷ 2400 = (20)/t

→ 5 = 20/t

→ 5t = 20

→ t = 20 ÷ 5

→ t = 4 seconds

Now, find the acceleration.

→ a = (v – u)/t

→ a = (30 – 10)/4

→ a = 20/4

→ a = 5 m/s²

Now, by using the third equation of motion,

→ v² – u² = 2as

s = distance

→ (30)² – (10)² = 2 × 5 × s

→ 900 – 100 = 10s

→ 800 = 10s

→ 800 ÷ 10 = s

→ 80 m = s

Therefore, distance travelled is 80 m.

4 0

3 years ago