<h3><u>Answer;</u></h3>
Centripetal acceleration = 0.931 m/s²
Centripetal force = = 1.234 × 10^-4 Newtons
<h3><u>Explanation;</u></h3>
Centripetal acceleration is given by the formula v²/r, where r is the radius of the circular path and v is the velocity of a body;
Centripetal acc = 3.2²/11
= 0.931 m/s²
Centripetal force is a force that acts on an object or a body in circular path and is directed towards the center of the circular path.
Centripetal force is given by the formula;
mv²/r ; where m is the mass of the body, r is the radius of the circular path and v is the velocity of a body;
mass = 33 mg or 1.33 × 10^-6 kg, velocity = 3.20 m/s and r = 11 m
Therefore;
Centripetal force = (1.33 ×10^-6 × 3.1²)/ 11
= 1.234 × 10^-4 Newtons
Answer:
Answer explained below
Explanation:
(a) The rays are diverging near the lens. They change the direction when they passed through the converging lens
(b) If the light rays don't bend they will move away from the optical (principal axis) as the other waves are moving.
(c) If we decrease the distance between lens and light source, most of the rays diverge and no ray converges on the screen even after passing through the lens. Here is a screenshot.
Answer:
Tarzan will be moving at 7.4 m/s.
Explanation:
From the question given above, the following data were obtained:
Height (h) of cliff = 2.8 m
Initial velocity (u) = 0 m/s
Final velocity (v) =?
NOTE: Acceleration due to gravity (g) = 9.8 m/s²
Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 2.8)
v² = 0 + 54.88
v² = 54.88
Take the square root of both side
v = √54.88
v = 7.4 m/s
Therefore, Tarzan will be moving at 7.4 m/s at the bottom.
Answer:
300 N/m
Explanation:
given,
Load attached to the spring, W = 54 N
length of stretch of the spring, x = 0.15 m
spring constant= ?
Force applied on the spring is calculated by the equation
F = k x
where k is the spring constant
x is the displacement of the spring due to applied load
now,
54 = k × 0.15
hence, the spring constant is equal to 300 N/m
Answer:
F = 3.6 kN, direction is 9.6º to the North - East
Explanation:
The force is a vector, so one method to find the solution is to work with the components of the vector as scalars and then construct the resulting vector.
Let's use trigonometry to find the component of the forces, let's use a reference frame where the x-axis coincides with the East and the y-axis coincides with the North.
Wind
X axis
F₁ = 2.50 kN
Tide
cos 30 = F₂ₓ / F₂
sin 30 = F_{2y} / F₂
F₂ₓ = F₂ cos 30
F_{2y} = F₂ sin 30
F₂ₓ = 1.20cos 30 = 1.039 kN
F_{2y} = 1.20 sin 30 = 0.600 kN
the resultant force is
X axis
Fₓ = F₁ₓ + F₂ₓ
Fₓ = 2.50 +1.039
Fₓ = 3,539 kN
F_y = F_{2y}
F_y = 0.600
to find the vector we use the Pythagorean theorem
F = 
F = 
F = 3,589 kN
the address is
tan θ = F_y / Fₓ
θ = tan⁻¹ 
θ = tan⁻¹ 
0.6 / 3.539
θ = 9.6º
the resultant force to two significant figures is
F = 3.6 kN
the direction is 9.6º to the North - East
