The most rapid period of growth and development occurs during infancy. Physical changes include doubling of birth weight, increased height, and development of sight and hearing.
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Answer:
The minimum speed the car must have at the top of the loop to not fall = 35 m/s
Explanation:
Anywhere else on the loop, the speed needed to keep the car in the loop is obtained from the force that keeps the body in circular motion around the loop which has to just match the force of gravity on the car. (Given that frictional force = 0)
mv²/r = mg
v² = gr = 9.8 × 25 = 245
v = 15.65 m/s
But at the top, the change in kinetic energy of the car must match the potential energy at the very top of the loop-the-loop
Change in kinetic energy = potential energy at the top
Change in kinetic energy = (mv₂² - mv₁²)/2
v₁ = velocity required to stay in the loop anywhere else = 15.65 m/s
v₂ = minimum velocity the car must have at the top of the loop to not fall
And potential energy at the top of the loop = mgh (where h = the diameter of the loop)
(mv₂² - mv₁²)/2 = mgh
(v₂² - v₁²) = 2gh
(v₂² - (15.65)²) = 2×9.8×50
v₂² - 245 = 980
v₂² = 1225
v₂ = 35 m/s
Hence, the minimum speed the car must have at the top of the loop to not fall = 35 m/s
Voltage=Energy/Charge, V=E/Q
V in volts V, E in joules J, Q in coulombs C.
or
Voltage= Current×Resistance, V=IR
V in volts V, I in amperes A and R in ohms Ω
Answer:
Explanation:
Following are the three important ways by which a body can get charged. ⇒ By conduction :When an uncharged body is made in contact with a charged body, the charge flow into the non charged body and the body gets charged. ⇒ By rubbing: When a body is rubbed with another body, both of them gets charged.
Answer:
Explanation:
When two ball of identical mass collides perfectly elastically , there is exchange of velocity between the two balls .
Here ball be was at rest initially . After collision ball A comes to rest , so there is complete exchange of velocity . Hence ball A must have same mass as that of B . mass of ball A = 1 kg .
b ) Due to complete exchange of velocity , velocity of ball A will be picked up by ball B . Hence velocity of ball B = 3.1416 m /s . Yes it will be moving in the direction of ball A .
c )
In case of perfectly inelastic collision they will become single mass
total mass = 2 kg
applying conservation of momentum law
their common velocity after collision = 1 x 3.1416 / 2 = 1.57 m /s
d )
Applying conservation of momentum law
initial momentum = Ma x va
they move in opposite direction after collision
their total momentum after collision
1 x va - Ma va
applying law of conservation of momentum
1 x va - Ma va = Ma va
va = 2Ma va
Ma = .5 kg .
