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3 years ago

In the visible light portion of the electromagnetic spectrum, each __________ is determined by its wavelength.

Physics

1 answer:

Archy [21]3 years ago

6 0

Answer:

A) color

Explanation:

Visible light is a portion of the electromagnetic spectrum, that includes wavelengths approximately from 380 nm to 750 nm.

It is the only part of the electromagnetic spectrum that the human eye can see. Depending on the wavelength of the light in this region, we perceive the light as a different color.

Therefore, each color is associated to a different range of wavelength, as follows:

Violet 380 - 450 nm

Blue 450 - 495 nm

Green 495 - 570 nm

Yellow 570 - 590 nm

Orange 590 - 620 nm

Red 620 - 750 nm

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If ram is 40kg and travels 200m in 30 sec find his power

WARRIOR [948]

Work done

N×200
mg200
40(10)(200)
400(200)
80000J

Power

Work done/Time
80000/30
8000/3
2668W

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3 years ago

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In an experiment refractive index of glass was observed to be 1.45,1.56,1.54,1.44,1.54and1.53. Calculate mean value of refractiv

Sever21 [200]

The mean may be calculated by summing the values of the refractive index and dividing the sum by the number of experiments. This is:
Mean = (1.45 + 1.56 + 1.54 + 1.44 + 1.54 + 1.53)/6
Mean = 1.51

The mean absolute error is the sum of the absolute values of errors divided by the number of trials:
MAE = (|1.45-1.51|+|1.56-1.51|+|1.54-1.51|+|1.44-1.51|+|1.54-1.51|+|1.53-1.51|)/6
MAE = 0.043

The fractional error is the MAE divided by the actual value:
Fractional error = 0.043 / 1.51
Fractional error = 43/1510

The percentage error is the fractional error multiplied by 100:
Percentage error = 2.85%

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4 years ago

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grigory [225]

Answer:

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3 years ago

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A 3.00 kg object is moving in the XY plane, with its x and y coordinates given by x = 5t³ !1 and y = 3t ² + 2, where x and y are

Hatshy [7]

Answer:

The net force acting on this object is 180.89 N.

Explanation:

Given that,

Mass = 3.00 kg

Coordinate of position of $x= 5t^3+1$

Coordinate of position of $y=3t^2+2$

Time = 2.00 s

We need to calculate the acceleration

$a = \dfrac{d^2x}{dt^2}$

For x coordinates

$x=5t^3+1$

On differentiate w.r.to t

$\dfrac{dx}{dt}=15t^2+0$

On differentiate again w.r.to t

$\dfrac{d^2x}{dt^2}=30t$

The acceleration in x axis at 2 sec

$a = 60i$

For y coordinates

$y=3t^2+2$

On differentiate w.r.to t

$\dfrac{dy}{dt}=6t+0$

On differentiate again w.r.to t

$\dfrac{d^2y}{dt^2}=6$

The acceleration in y axis at 2 sec

$a = 6j$

The acceleration is

$a=60i+6j$

We need to calculate the net force

$F = ma$

$F = 3.00\times(60i+6j)$

$F=180i+18j$

The magnitude of the force

$|F|=\sqrt{(180)^2+(18)^2}$

$|F|=180.89\ N$

Hence, The net force acting on this object is 180.89 N.

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4 years ago

Which has greater accuracy, the 10 mL graduated cylinder or the 50 mL graduated cylinder

mylen [45]

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3 years ago

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