Answer:
1.4 * 10 ^-1 Ω
Explanation:
Hi,
For this question, we gotta use the formula
R = pL/A
p = The resistivity of your material at 20°C
L = length of the wire
A = cross-sectional area
The resistivity of tungsten is 5.60 * 10^-8 at 20°C
By plugging the values, we get:
R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω
Answer:
The magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Explanation:
Given;
speed of the electron, v = 8.0 × 10⁶ m/s
magnetic field strength, B = 2.5 T
angle of inclination of the field, θ = 60°
The magnetic force experienced by the electron in the magnetic field is given as;
F = qvBsinθ
where;
q is charge of electron = 1.6 x 10⁻¹⁹ C
B is strength of magnetic field
v is speed of the electron
Substitute the given values and solve for F
F = (1.6 x 10⁻¹⁹)( 8.0 × 10⁶)(2.5)sin60
F = 2.77 x 10⁻¹² N
Thus, the magnitude of the magnetic force of the electron is 2.77 x 10⁻¹² N
Answer:
θ = 21.8º
Explanation:
We can solve this exercise using Newton's conditions for equilibrium, in the attached we can see a diagram of the forces.
The most used coordinate system is an axis parallel to the plane (x axis) and an axis perpendicular to the plane (y axis), let's write Newton's equations on this axes
Y Axis
N- 
= 0
N =
X axis
fr - Wₓ = 0 (1)
Let's use trigonometry to find the normal ones
sin θ = Wₓ / W
cos θ = / W
Wx = W sin θ
= W cos θ
The friction force has the formula
fr = μ N
fr = μ (W cos θ)
We substitute in 1
μ mg cosθ = mg sin θ
μ cos θ = sin θ
tan θ = μ
θ = tan⁻¹ μ
calculate
θ = tan⁻¹ 0.40
θ = 21.8º
Average speed = (total distance) / (total time)
First segment:
15 m/s for 10 sec; distance covered = (15 x 10) = 150 m
Second segment:
20 m/s for 20 sec; distance covered = (20 x 20) = 400 m
Third segment:
30 m/s for 15 sec; distrance covered = (30 x 15) = 450 m
Total time = (10s + 20s + 15s) = 45 sec
Total distance = (150m + 400m + 450m) = 1,000 m (1 km)
<em>Average speed</em> = (1,000 m) / (45 sec) = <em>22.22 m/s</em>
Becomes a +1 ion for this
