The quantity that has a magnitude of zero when the ball is at the highest point in its trajectory is
the vertical velocity.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity

, where

- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration

directed downwards, and with initial velocity

. Due to the presence of the acceleration g on the vertical direction (pointing in the opposite direction of the initial vertical velocity), the vertical velocity of the ball decreases as it goes higher, up to a point where it becomes zero and it reverses its direction: when the vertical velocity becomes zero, the ball has reached its maximum height.
Answer:
Mass of the silver will be equal to 46.70 gram
Explanation:
We have given heat required to raise the temperature of silver by 24°C is 269 J , so 
Specific heat of silver = 0.240 J/gram°C
We have to find the mass of silver
We know that heat required is given by
, here m is mass, c is specific heat of silver and
is rise in temperature
So 
m = 46.70 gram
So mass of the silver will be equal to 46.70 gram
Answer:

Explanation:
Unit conversions:
1890 km/h = 1890 km/h * 1000m/km * 1/3600 h/s = 525 m/s
5.2 km = 5200 m
Assume that the jets is traveling in perfect circular motion, we can calculate the centripetal acceleration of the motion:

where v = 525m/s is the velocity of the jet and r = 5200 is the radius of the arc

KE = (1/2) (mass) (speed)²
KE = (1/2) (20 kg) (40 m/s)²
KE = (1/2) (20 kg) (1,600 m²/s²)
KE = (10 kg) (1,600 m²/s²)
KE = 16,000 Joules
Answer:
A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.
Explanation:
The bulk modulus is represented by the following differential equation:

Where:
- Bulk module, measured in pascals.
- Sample volume, measured in cubic meters.
- Local pressure, measured in pascals.
Now, let suppose that bulk remains constant, so that differential equation can be reduced into a first-order linear non-homogeneous differential equation with separable variables:

This resultant expression is solved by definite integration and algebraic handling:




The final volume is predicted by:

If
,
and
, then:


Change in volume due to increasure on pressure is:



A volume of a cubic meter of water from the surface of the lake has been compressed in 0.004 cubic meters.