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FinnZ [79.3K]
3 years ago
5

Like charges will exert a force of

Physics
2 answers:
natulia [17]3 years ago
7 0

Answer:

D- Repulsion

Explanation:

A positively charged object will exert a repulsive force upon a second positively charged object.

Vlad1618 [11]3 years ago
6 0
Repulsión can someone help me ? What is the summary of chapter 27 book two roads by Joseph
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If you travel from Yakima to Ellensburg (Yakima to Ellensburg is 50 miles) with a speed of 60 miles/hour for half of the
koban [17]

Answer:

\displaystyle \frac{480}{7}\approx 68.6\; \rm mph.

Explanation:

The average speed of an object is equal to total distance over total time.

  • Distance traveled: \rm 50 \; mi.

How much time is taken? This trip is divided into two halves, each of distance \displaystyle \frac{50}{2} = 25\;\rm mi.

Time spent on the first half of the trip:

\displaystyle t_1 = \frac{s_1}{v_1} = \frac{25}{60} = \frac{5}{12}\; \rm hours.

Similarly, time spent on the second half of the trip:

\displaystyle t_2 = \frac{s_2}{v_2} = \frac{25}{80} = \frac{5}{16}\; \rm hours.

In total:

\displaystyle \frac{5}{12} + \frac{5}{16} = \frac{35}{48} \; \rm hours.

Average speed:

\begin{aligned} \text{Average speed} &= \frac{\text{Total Distance}}{\text{Total Time}}\\ &= 50 \left/\frac{35}{48}\right.\\ &= 50 \cdot \frac{48}{35} \\&= \frac{480}{7}\approx 68.6\; \rm mph \end{aligned}.

This value turned out to be slightly different from the average of the speed during the two halves of the journey. The reason is that the object traveled at each speed for a different amount of time. It spent more time at the slower speed, which gives that speed a greater weight in the average. That explains why the average speed is closer to \rm 60\; mph rather than \rm 80\; mph.

3 0
3 years ago
A block weighing 9.3 N requires a force of 3.7 N to push it along at constant velocity. What is the coefficient of friction for
olga_2 [115]

Answer:

0.398

Explanation:

According to friction, the frictional force is directly proportional to the normal reaction

Ff = nR

Ff is the frictional force

n is the coefficient of friction

R is the reaction

Reaction is equal to the weight

R= W = 9.3N

Fm = Ff = 3.7N

Fm is the moving force

Get the coefficient of friction

n = Ff/R

n = 3.7/9.3

n = 0.398

Hence the coefficient of friction for the surface is 0.398

3 0
3 years ago
I walk 500 meters due east from my home and then walk 866
mars1129 [50]

The magnitude of the total displacement is 1000 m

Explanation:

Displacement is a vector quantity connecting the initial position and final position of motion of an object.

The magnitude of the displacement is therefore the distance in a straight line between the initial and final position of motion.

The person in the problem has the following motions:

500 meters due east

866 meters due north

The two motions are perpendicular to each other, so they form the sides of a right triangle, of which the hypothenuse corresponds to the magnitude of the total displacement.

Therefore, the magnitude of the displacement can be simply found by using Pythagorean's theorem:

d=\sqrt{d_x^2+d_y^2}=\sqrt{500^2+866^2}=1000 m

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

4 0
4 years ago
♡ GuYs diG cRaZy cHiCks ♡ IvE naMeD my aLtEr Ego AJ
Sonja [21]

Answer:

cooooooooooooooollllllllll

Explanation:

8 0
3 years ago
A 2-way light bulb for a 110 V lamp has filament that uses power at a rate of 50.0 W. What is the resistance of the filament?
Novosadov [1.4K]

Answer:r=242ohms

Explanation:

Power(p)=50w

Volt(v)=110v

Resistance(r)=?

Power(p)=((volt)^2)/(resistance(r))

50=110^2/r

Cross product

50xr=110^2

50r=12100

r=12100/50

r=242ohms

3 0
3 years ago
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