The particle has a constant horizontal velocity, and a vertical force won't affect the horizontal speed, so it should be fairly easy to find the last part, "the time taken for a 10m horizontal displacement," using a kinematic equation.
X = x + vt + (1/2)at²
10 = 0 + (1.6)t + (1/2)(0)t²
10/1.6 = t
t = 6.25s
So now we have to find the vertical displacement over 6.25 seconds on a particle of a 2.5kg mass with a force of 8N.
Start with Newton's second law.
F = ma
8 = (2.5)a
a = 3.2m/s²
Now, use kinematics again.
Y = y + vt + (1/2)at²
Y = 0 + (0)(6.25) + (1/2)(3.2)(6.25)²
Y = <u>62.5m</u>
Answer:
218.5 N
Explanation:
In order for the sled to be in equilibrium along the vertical direction, the forces acting along this direction must be balanced. So the equilibrium equation is:
where
N is the normal force
F = 50 N is the force that pulls the sled
is the angle between the force and the horizontal, so
is the component of F acting along the vertical direction
(mg) is the weight of the sled, with
m = 25 kg being the mass of the sled
g = 9.8 m/s^2 is the acceleration due to gravity
Solving the formula for N, we find
The charge of 1 mole of proton is equivalent to 1.60217656x10^-19 coulombs. This is also called an elementary charge. Multiply that by 3 to get the net charge of three moles of protons.
Charge of 3 mol protons = 3 x 1.60217656x10^-19 = 4.81x10^-19 coloumbs
So the answer is <span>c) 4.81×10 −19 C</span>
True, scientific law does explain something that will happen under certain circumstances
