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riadik2000 [5.3K]
3 years ago
5

The amount of heat needed

Physics
1 answer:
Masteriza [31]3 years ago
4 0
J=joules, c=specific heat, q= energy, and the Tf and Ti are the final and initial temperatures cause I couldn't find a delta sign.

Q=mc(T_{f}-T_{I})  \\ 33000j=2kg*c*80 \\\frac{33000j}{2kg*80} =c \\ c=206.25jkg^{-1}
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Explanation:

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Answer:

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