Question

A spring extends by .16 meters when pulled with 20 N of Force. What is the Potential Energy in the spring at this extension?

Answer 1

Answer:

Potential energy = 1.6 J

Work done = -1.6 J

Explanation:

Potential Energy in the spring at this extension?

The potential energy U in the spring is U = 1/2kx² where k = spring constant = F/x where F = force = 20 N and x = extension = 0.16 m. So k = 20 N/0.16 m = 125 N/m

U = 1/2kx²

= 1/2 × 125 N/m × (0.16 m)²

= 1.6 J

What is the work done to extend the spring. 16 meters

Work done W = U₁ - U₂ where U₁ = initial potential energy = 0 and U₂ = final potential energy = 1.6 J

W = 0 - 1.6 J

   = -1.6 J