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3 years ago

A 62 kg skydiver moving at terminal speed falls 50 m in 1 s. What power is the skydiver expending on the air?

Physics

1 answer:

IgorLugansk [536]3 years ago

3 0

Answer:

P = 30380 W

Explanation:

given,

mass of the skydiver, m = 62 Kg

distance, s = 50 m

time, t = 1 s

we know,

$Power= \dfrac{work\ done}{time}$

$Power= \dfrac{F.s}{t}$

F = m g

$Power= \dfrac{m g.s}{t}$

inserting all the values

$P = \dfrac{62\times 9.8\times 50}{1}$

P = 30380 W

hence, Power the skydiver expending on the air is 30380 W

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Explanation:

Hello!

To solve this problem we are going to use the ideal gass law

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