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3 years ago

A 62 kg skydiver moving at terminal speed falls 50 m in 1 s. What power is the skydiver expending on the air?

Physics

1 answer:

IgorLugansk [536]3 years ago

3 0

Answer:

P = 30380 W

Explanation:

given,

mass of the skydiver, m = 62 Kg

distance, s = 50 m

time, t = 1 s

we know,

$Power= \dfrac{work\ done}{time}$

$Power= \dfrac{F.s}{t}$

F = m g

$Power= \dfrac{m g.s}{t}$

inserting all the values

$P = \dfrac{62\times 9.8\times 50}{1}$

P = 30380 W

hence, Power the skydiver expending on the air is 30380 W

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Answer with Explanation:

We are given that

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We know that magnetic flux

$\phi=BA$

Emf , $E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid$

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Current, $I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid$

Substitute t=0 s

Then, I= $1.6\mid (1-0)\mid$ =1.6 A

Substitute t=1 s

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Substitute

t=2 s

Current, I= $1.6\mid(1-2)\mid$ =1.6 A

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A temperature of 200 degrees F is equivalent to approximately

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(1) Changing Fahrenheit to Celsius:
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C = (200-32) * (5/9) = 93.333334 degrees Celsius

(2) Changing the Fahrenheit to kelvin:
The formula used to convert from Fahrenheit to kelvin is as follows:
K = <span>(F - 32) * 5/9 + 273.15
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jarptica [38.1K]

Answer:

FALSE!!!

Explanation:

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What is the intensity of a sound with a measured intensity level of 84 db? (i0 = 10-12 w/m2)?

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