In order to determine the results from a father who is homozygous recessive for the tongue rolling trait, T, and a mother who is heterozygous for the trait, a Punett square can be used to determine both the resulting genotype (allele combination) and phenotype (observable characteristics). The results are 50% Tt and 50% tt. Thus, the cross would result to 1:1 ratio of tongue rolling to non-tongue rolling offsprings.
Answer:
Red allele frequency will be highest in population II
Population III can undergo bottleneck effect
The frequency of the brown allele will least likely be altered in the population I
Explanation:
Population I -
Total population -
Brown birds -
Red birds -
Population II
Total population -
Brown birds -
Red birds -
Population III
Total population -
Brown birds -
Red birds -
Frequency of red birds in population I
Frequency of red birds in population II
Frequency of red birds in population III
Red allele frequency will be highest in population II and it will be equal to as compared to in case of population I and III
Population III can undergo bottleneck effect because of smaller population size
The frequency of the brown allele will least likely be altered in the population that has highest brown individual , i.e population I
Answer:
hey dad can i have some money
if he says no
then no
Explanation:
Answer:
amino acids
Explanation:
(if you are confused, I recommend watching the videos from Khan Academy and The Amoeba Sisters.)