<h3><u>Answer;</u></h3>
Are moving up and down.
As a transverse wave travels through a rope from left to right, the parts of the rope <u>are moving up and down</u>.
<h3><u>Explanation;</u></h3>
- Transverse waves occur when a disturbance causes oscillations perpendicular to the propagation, that is the direction of energy transfer.
- <em><u>Particles of the medium move perpendicular to the direction the transverse wave itself is moving. For example, if the wave is moving to the right, the particles of the medium are moving up and down.</u></em>
- <em><u>Therefore, as a transverse wave travels through a rope from left to right, the parts of the rope are moving up and down.</u></em>
Don't over think it!
For example, if you do 5 laps in 5 minutes then you do one lap per minute. If you use that example and you apply it to your problem you'll notice that the answer is simply C. 1km/min.
Best wishes!
Answer:
a cornea that is not curved enough
Answer:
22kj
Explanation:
set h = 0 at the end of slide.
final height is -12m
initial condition will be Ui = 0
Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J
Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J
Ki = 1/2mv²
Ki= 1/2 x 61 x (16)² = 7808J
conservation energy says that
Ui + Ki = Uf +Kf +ΔEth
so ΔEth = Ui + Ki - Uf - Kf
ΔEth = 22234.5 - 7808 + 7173
ΔEth = 21600J
ΔEth =22Kj
