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frez [133]
3 years ago
9

Neutralization Reactions

Chemistry
1 answer:
marta [7]3 years ago
4 0

Answer:

2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O

Explanation:

2HNO3+ Ba(OH)2 = Ba(NO3)2 + 2H2O

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + 6H2O

H+

O2-

OH-

Ba2+

Ca2+

NO3-

P 5+, 3+, 3-

H2O

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A 18.00 g g milk chocolate bar is found to contain 11.00 g g of sugar.1. How many milligrams of sugar does the milk chocolate ba
horrorfan [7]

Answer:

1. 1.100x10⁴mg

2. 2444mg

Explanation:

1. The 18.00g milk chocolate bar contain 11.00g of sugar. In miligrams:

11.00g * (1000mg / 1g) = 1.100x10⁴mg

2. If a bar of 18.00g contain 11.00g of sugar, a bar of 4.000g will contain:}

4.000g bar * (11.00g / 18.00g)  = 2.444g of sugar.

In miligrams:

2.444g * (1000mg / 1g) = 2444mg

6 0
3 years ago
Describe how to write the Ksp.
adoni [48]

b2+ + 2 NO3- + 2 Na+ + 2 I- >> PbI2 (s) + 2 Na+ + 2 NO3-  


net ionic

Pb2+ + 2 I- >> PbI2  


Ksp = [Pb2+] [I-]^2  


Ksp = 7.1 x 10^-9  


molar solubility

let x = mol/L of Pb2+ that dissolve . This will give x mol/L Pb2+ and 2x mol/L I-  


7.1 x 10^-9 = (x) (2x)^2 = 4x^3  


molar solubility = 0.0012 M

~~thanks to google research~~

6 0
3 years ago
Read 2 more answers
A . When atoms share electrons to fill their outermost energy levels, they form _________ bonds.
klasskru [66]
A. Covelant bonds
B. Ionic bonds
7 0
3 years ago
3. What is the primary consumer in the following food chain, sun - tomato plant - tomato worm - wasp?
Julli [10]

Answer:

Tomato worm  

Explanatio

v

vv

5 0
2 years ago
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Light travels at a rate of 3.00 x 10^8 m/s. It takes light 8.30 min to travel from the surface of the sun to the earth. What is
bija089 [108]

Answer: The distance of the earth from the sun is 1.494\times 10^{11}m

Explanation:

Speed of light = 3.00\times 10 ^8 m/s

Time taken to travel from sun to earth = 8.30 mins = 8.3\times 60=498sec    (1min=60 s)

As we know ; Speed is defined as the distance travelled per unit time.

Distance=speed\times time

Hence distance between sun and earth =3.00\times 10^8m/s\times 498s=1.494\times 10^{11}m

Thus the distance of the earth from the sun is 1.494\times 10^{11}m

7 0
3 years ago
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