Write the electronic configuration of calcium and potassium.
2 answers:
Answer:
<h3>Electronic configuration of Potassium (K) </h3>Atomic number of potassium = 19
Therefore number of electrons = 19
Since, maximum number of electrons in outermost orbit will not be more than 8, thus the 19th electron of potassium atom will reside in 4th.
Thus, electronic configuration of potassium is
given in first pic.
Number of orbit in potassium = 4
<h3>Electronic configuration of Calcium (Ca) </h3>Atomic number of calcium = 20
Therefore number of electrons = 20
Thus, electronic configuration of calcium is given in sec pic.
Number of orbit in calcium = 4
Explanation:
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Explanation:
The given data is as follows.
Vapour pressure of pure = 33.85 Torr
Temperature = 298 K
Mole fraction of = 122.36 torr
Therefore, calculate the vapor pressure of as follows.
Vapour pressure of = mole fraction of
x K of
= 0.050 x 122.36 Torr
= 6.118 Torr
So, vapor pressure of is 6.118 Torr
.
Now, calculate the vapor pressure of carbon tetrachloride as follows.
Vapour pressure of = mole fraction of
x Pressure of
= (1 - 0.050) × 33.85 Torr
= 32.1575 Torr
So, vapor pressure of is 32.1575 Torr .
Hence, the total pressure will be as follows.
= 6.118 Torr + 32.1575 Torr
= 38.2755 Torr
Therefore, composition of =
= 0.8405
Composition of is 0.8405
.
And, composition of =
= 0.1598
Composition of is 0.1598
.